python抓取google搜索url
import sysurl = ('https://ajax.googleapis.com/ajax/services/search/web''?v=1.0&q=%s&rsz=8&start=%s') % (search,page)try: request = urllib2.Request( url, None, {'Referer': 'http://www.baidu.com'}) response = urllib2.urlopen(request) # Process the JSON string. results = simplejson.load(response) info = results['responseData']['results']except Exception,e: print e time.sleep(5) continue for minfo in info: for key in minfo.keys(): if key == 'url': try: print 'url:%s' % minfo[key]