subprocess.Popen怎么才能迅速显示命令输出的信息

subprocess.Popen如何才能迅速显示命令输出的信息

Python code

#import subprocessclass NetDetect:        def __init__(self, addr):        self.addr = addr        self.log = open( 'NetDetect.log', 'w' )        if self.log == None:            print 'Open NetDetect.log failed'            def __del__(self):        if self.fdp:            self.fdp.kill()        if self.log:            self.log.close()            def ping(self):        self.fdp = subprocess.Popen( [ 'ping', self.addr, '-t' ], stdout = subprocess.PIPE )        for line in self.fdp.stdout:            print line,            self.log.write( line )        self.fdp = Noneif __name__ == '__main__' :        nd = NetDetect( 'www.sina.com.cn' )    nd.ping()

Python code

import subprocessclass NetDetect:        def __init__(self, addr):        self.addr = addr        self.log = open( 'NetDetect.log', 'w' )        if self.log == None:            print('Open NetDetect.log failed')            def __del__(self):        if self.fdp:            self.fdp.kill()        if self.log:            self.log.close()            def ping(self):        self.fdp = subprocess.Popen( [ 'ping', self.addr, '-t' ], stdout = subprocess.PIPE )        for line in self.fdp.stdout:            print(line.decode("gb2312"))            self.log.write(line.decode("gb2312"))            self.log.flush()        self.fdp = Noneif __name__ == '__main__' :        nd = NetDetect( 'www.sina.com.cn' )    nd.ping()
[解决办法]
嗯，3版的可以跑，还用2版嘛就试试下面dev版本...
http://code.google.com/p/subprocdev/source/browse/subprocess.py?name=default
[解决办法]
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上述代码稍微修改下，在XP系统下， python 3.2.2 版本下运行正常，代码如下所示：
Python code

import subprocess

class NetDetect:
    
    def __init__(self, addr):
        self.addr = addr
        self.log = open( 'NetDetect.log',……