是jqGrid "Array Data"例子问题?
今天在做jqGrid例子时,发现Array Data有个问题,写下来问问大家
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"><html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en" lang="en"><head><meta http-equiv="Content-Type" content="text/html; charset=gbk" /><title>jqGrid Demos</title><link rel="stylesheet" type="text/css" media="screen" href="themes/redmond/jquery-ui-1.7.1.custom.css" /><link rel="stylesheet" type="text/css" media="screen" href="themes/ui.jqgrid.css" /><link rel="stylesheet" type="text/css" media="screen" href="themes/ui.multiselect.css" /><script src="js/jquery.js" type="text/javascript"></script><script src="js/jquery-ui-1.7.2.custom.min.js" type="text/javascript"></script><script src="js/jquery.layout.js" type="text/javascript"></script><script src="js/i18n/grid.locale-en.js" type="text/javascript"></script><script type="text/javascript">$.jgrid.no_legacy_api = true;$.jgrid.useJSON = true;</script><script src="js/jquery.jqGrid.min.js" type="text/javascript"></script><script src="js/jquery.tablednd.js" type="text/javascript"></script><script src="js/jquery.contextmenu.js" type="text/javascript"></script><script src="js/ui.multiselect.js" type="text/javascript"></script><script type="text/javascript"> jQuery(document).ready(function(){ jQuery("#list4").jqGrid({ datatype: "local",height: 250, colNames:['Inv No','Date', 'Client', 'Amount','Tax','Total','Notes'], colModel:[ {name:'id',index:'id', width:60, sorttype:"int"}, {name:'invdate',index:'invdate', width:90, sorttype:"date"}, {name:'name',index:'name', width:100}, {name:'amount',index:'amount', width:80, align:"right",sorttype:"float"}, {name:'tax',index:'tax', width:80, align:"right",sorttype:"float"}, {name:'total',index:'total', width:80,align:"right",sorttype:"float"}, {name:'note',index:'note', width:150, sortable:false} ], multiselect: true, caption: "Manipulating Array Data"});var mydata = [ {id:"1",invdate:"2007-10-01",name:"test",note:"note",amount:"200.00",tax:"10.00",total:"210.00"}, {id:"2",invdate:"2007-10-02",name:"test2",note:"note2",amount:"300.00",tax:"20.00",total:"320.00"}, {id:"3",invdate:"2007-09-01",name:"test3",note:"note3",amount:"400.00",tax:"30.00",total:"430.00"}, {id:"4",invdate:"2007-10-04",name:"test",note:"note",amount:"200.00",tax:"10.00",total:"210.00"}, {id:"5",invdate:"2007-10-05",name:"test2",note:"note2",amount:"300.00",tax:"20.00",total:"320.00"}, {id:"6",invdate:"2007-09-06",name:"test3",note:"note3",amount:"400.00",tax:"30.00",total:"430.00"}, {id:"7",invdate:"2007-10-04",name:"test",note:"note",amount:"200.00",tax:"10.00",total:"210.00"}, {id:"8",invdate:"2007-10-03",name:"test2",note:"note2",amount:"300.00",tax:"20.00",total:"320.00"}, {id:"9",invdate:"2007-09-01",name:"test3",note:"note3",amount:"400.00",tax:"30.00",total:"430.00"} ]; for(var i=0;i<=mydata.length;i++) //jqgrid_demo35中用这个方法,发现不能加载数据 // jQuery("#list4").jqGrid('addRowData',i+1,mydata[i]); //我改用以下方法就可以成功加载,不知为什么?还请高手指点??? jQuery("#list4").addRowData(i+1,mydata[i]); }); </script> <body> <table id="list4"></table></body></html>?
1 楼 zuozhengfeng 2010-02-03 我两个都不行，更是不知道什么原因啊 2 楼 guilipan 2010-02-09 jqgrid3.6版本以上才支持你上面注释的方法，3.6之前的版本你用下面的方法是可以的 3 楼 zuozhengfeng 2010-02-09 后来没有办法把上面这个例子复制了，可以运行，再一行一行的增加，最终也就可以了，还不是很清楚上面原因，但是可以正常运行了 4 楼 konglx 2010-05-09 哦,谢谢指点