XML/map相互转换
import java.io.IOException;
import java.io.Reader;
import java.io.StringReader;
import java.util.ArrayList;
import java.util.HashMap;
import java.util.Iterator;
import java.util.List;
import java.util.Map;
import org.jdom.Attribute;
import org.jdom.Document;
import org.jdom.Element;
import org.jdom.JDOMException;
import org.jdom.input.SAXBuilder;
import org.jdom.output.Format;
import org.jdom.output.XMLOutputter;
public class XmlUtil {
?/**
? * 取得xml文件的根节点名称，即消息名称。
? * @param xmlStr xml内容
? * @return String 返回名称
? */
?public static String getRootName(String xmlStr) throws Exception {
??SAXBuilder builder = new SAXBuilder();
??Document doc = builder.build(new StringReader(xmlStr));
??Element root = doc.getRootElement();
??return root.getName();
?}
?
?/**
? * 把xml文件转换为map形式，其中key为有值的节点名称，并以其所有的祖先节点为前缀，用
? * "."相连接。如：SubscribeServiceReq.Send_Address.Address_Info.DeviceType
? * @param xmlStr xml内容
? * @return Map 转换为map返回
? */
?public static Map<String , String> xml2Map(String xmlStr) throws JDOMException, IOException {
??Map<String , String> rtnMap = new HashMap<String , String>();
??SAXBuilder builder = new SAXBuilder();
??Document doc = builder.build(new StringReader(xmlStr));
??// 得到根节点
??Element root = doc.getRootElement();
??String rootName = root.getName();
??rtnMap.put("root.name", rootName);
??// 调用递归函数，得到所有最底层元素的名称和值，加入map中
??convert(root, rtnMap, rootName);
??return rtnMap;
?}
?/**
? * 递归函数，找出最下层的节点并加入到map中，由xml2Map方法调用。
? * @param e xml节点，包括根节点
? * @param map 目标map
? * @param lastname 从根节点到上一级节点名称连接的字串
? */
?public static void convert(Element e, Map<String , String> map, String lastname) {
??if (e.getAttributes().size() > 0) {
???Iterator it_attr = e.getAttributes().iterator();
???while (it_attr.hasNext()) {
????Attribute attribute = (Attribute)it_attr.next();
????String attrname = attribute.getName();
????String attrvalue = e.getAttributeValue(attrname);
????map.put(lastname + "." + attrname, attrvalue);
???}
??}
??List children = e.getChildren();
??Iterator it = children.iterator();
??while (it.hasNext()) {
???Element child = (Element) it.next();
???String name = lastname + "." + child.getName();
???// 如果有子节点，则递归调用
???if (child.getChildren().size() > 0) {
????convert(child, map, name);
???} else {
????// 如果没有子节点，则把值加入map
????map.put(name, child.getText());
????// 如果该节点有属性，则把所有的属性值也加入map
????if (child.getAttributes().size() > 0) {
?????Iterator attr = child.getAttributes().iterator();
?????while (attr.hasNext()) {
??????Attribute attribute = (Attribute)attr.next();
??????String attrname = attribute.getName();
??????String attrvalue = child.getAttributeValue(attrname);
??????map.put(name + "." + attrname, attrvalue);
?????}
????}
???}
??}
?}
?/**
? * 把xml文件转换为list形式，其中每个元素是一个map，map中的key为有值的节点名称，并以其所有的祖先节点为前缀，用
? * "."相连接。如：SubscribeServiceReq.Send_Address.Address_Info.DeviceType
? * @param xmlStr xml内容
? * @return Map 转换为map返回
? */
?public static List<Map<String,String>> xml2List(String xmlStr) throws JDOMException, IOException {
??List<Map<String,String>> rtnList = new ArrayList<Map<String,String>>();
??Map<String , String> rtnMap = new HashMap<String , String>();
??SAXBuilder builder = new SAXBuilder();
??Document doc = builder.build(new StringReader(xmlStr));
??// 得到根节点
??Element root = doc.getRootElement();
??String rootName = root.getName();
??rtnMap.put("root.name", rootName);
??// 调用递归函数，得到所有最底层元素的名称和值，加入map中
??convert2List(root, rtnMap, rootName, rtnList);
??if(rtnList.size()==0)
???rtnList.add(rtnMap);
??return rtnList;
?}
?/**
? * 递归函数，找出最下层的节点并加入到map中，如果有相同的节点，则加入list中，
? * 由xml2List方法调用。
? * @param e xml节点，包括根节点
? * @param map 目标map
? * @param lastname 从根节点到上一级节点名称连接的字串
? * @param list 相同节点生成map放入list中
? */
?public static void convert2List(Element e, Map<String , String> map, String lastname, List<Map<String,String>> list) {
??if (e.getAttributes().size() > 0) {
???Iterator it_attr = e.getAttributes().iterator();
???while (it_attr.hasNext()) {
????Attribute attribute = (Attribute)it_attr.next();
????String attrname = attribute.getName();
????String attrvalue = e.getAttributeValue(attrname);
????map.put(lastname + "." + attrname, attrvalue);
???}
??}
??List children = e.getChildren();
??Iterator it = children.iterator();
??while (it.hasNext()) {
???Element child = (Element)it.next();
???String name = lastname + "." + child.getName();
???// 如果有子节点，则递归调用
???if (child.getChildren().size() > 0) {
????convert(child, map, name);
???} else {
????// 如果没有子节点，则把值加入map
????map.put(name, child.getText());
????// 如果该节点有属性，则把所有的属性值也加入map
????if (child.getAttributes().size() > 0) {
?????Iterator attr = child.getAttributes().iterator();
?????while (attr.hasNext()) {
??????Attribute attribute = (Attribute)attr.next();
??????String attrname = attribute.getName();
??????String attrvalue = child.getAttributeValue(attrname);
??????map.put(name + "." + attrname, attrvalue);
?????}
????}
???}
???//如果有相同节点，则加入list中，不考虑子节点中又有相同节点的情况
???if(e.getChildren(child.getName()).size()>1){
????Map<String,String> aMap = new HashMap<String,String>();
????aMap.putAll(map);
????list.add(aMap);
????map= new HashMap<String,String>();
????map.put("root.name", aMap.get("root.name"));
???}
??}
?}
?/**
? * 打印map 的所有key和value
? * @param map
? */
?public static void printMap(Map<String , String> map) {
??Iterator<String> keys = map.keySet().iterator();
??while (keys.hasNext()) {
???String key =? keys.next();
???System.out.println(key + ":" +? map.get(key));
??}
?}
?
??? /**
???? * 格式化xml
???? * @param xmlStr
???? * @param encode
???? * @return String
???? * @date Apr 30, 2008
???? */
??? @SuppressWarnings("deprecation")
?public static String formatXml(String xmlStr, String encode ) {
??? ??
??SAXBuilder sb = new SAXBuilder();
??Reader reader = new StringReader(xmlStr);
??
??Document doc = null;
??try {
???doc = sb.build(reader);
??}
??catch (Exception e) {
???//do nosth
??}
??
??XMLOutputter outputter = new XMLOutputter(Format.getPrettyFormat());
??????? outputter.setEncoding(encode);
??String result = "" ;
??if(null != doc){
???result = outputter.outputString(doc);
??}
??
??return result;
?}
}
