如何使用send()发送16进制数。
send(f_socket,buffer,strlen(buffer)+1,0);
buffer我定义的是一个字符串,我想让它在发送的时候转换为16进制数发送出去。如何获得。
[解决办法]
void HexDump(char *buf,int len) {
int i,j,k;
char binstr[80];
for (i=0;i<len;i++) {
if (0==(i%16)) {
sprintf(binstr,"%04x -",i);
sprintf(binstr,"%s %02x",binstr,(unsigned char)buf[i]);
} else if (15==(i%16)) {
sprintf(binstr,"%s %02x",binstr,(unsigned char)buf[i]);
sprintf(binstr,"%s ",binstr);
for (j=i-15;j<=i;j++) {
sprintf(binstr,"%s%c",binstr,('!'<buf[j]&&buf[j]<='~')?buf[j]:'.');
}
printf("%s\n",binstr);
} else {
sprintf(binstr,"%s %02x",binstr,(unsigned char)buf[i]);
}
}
if (0!=(i%16)) {
k=16-(i%16);
for (j=0;j<k;j++) {
sprintf(binstr,"%s ",binstr);
}
sprintf(binstr,"%s ",binstr);
k=16-k;
for (j=i-k;j<i;j++) {
sprintf(binstr,"%s%c",binstr,('!'<buf[j]&&buf[j]<='~')?buf[j]:'.');
}
printf("%s\n",binstr);
}
}
memcpy(buffer,"\x0a\x0b",2);
if( memcmp(buffer,"\x0a\x0b",2) == 0 )
{
//do something
}