（Problem 1）Multiples of 3 and 5
If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. The sum of these multiples is 23.
Find the sum of all the multiples of 3 or 5 below 1000.
#include <stdio.h>#include <string.h>#include <ctype.h> void solve(){ int sum,i; sum=0; for(i=3; i<1000; i++) { if(i%3==0 || i%5==0) { sum+=i; } } printf("%d\n",sum); } int main(){ solve(); return 0;}?
Answer:233168