求求教高手！！！！！！
下面是我写的一个简单登录界面：用户名和密码都保存在文件中。。。。总是出现异常说是３７行有错，但是就是没有找到。。符号都是对的。。。
异常：
type Exception report
message
description The server encountered an internal error () that prevented it from fulfilling this request.
exception
org.apache.jasper.JasperException: Exception in JSP: /Login.jsp:37
34: out.print(code+ " <BR> ");
35: out.print(usercode+ " <BR> ");
36:
37: if(username.equals(name)&&usercode.equals(code))
38: out.print( "Log In Successly ");
39: else
40: out.print( "Log In Failed ");
代码：
<%@page contentType= "text/html " import= "java.io.* "%>
<%@page pageEncoding= "UTF-8 "%>
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN "
"http://www.w3.org/TR/html4/loose.dtd ">
<html>
<head>
<meta http-equiv= "Content-Type " content= "text/html; charset=UTF-8 ">
<title> 简单的用户登录界面 </title>
</head>
<body>
<form action= "Login.jsp " method= "post ">
<table border= "1 " cellspacing= "1 " cellpadding= "4 " width= "80% " align= "center ">
<tr bgcolor= "pink "> <td colspan= "2 "> <font color= "blue "> 会员登录 </font> </td> </tr>
<tr> <td width= "21% "> 用户名: </td>
<td width= "59 "> <input type= "text " name= "username "> </td> </tr>
<tr> <td width= "21% "> 密码: </td>
<td width= "59 "> <input type= "password " name= "usercode "> </td> </tr>
</table>
<center> <input type= "submit " name= "loginsubmit " value= "会员登录 "> </center>
<% String username=request.getParameter( "username ");
String usercode=request.getParameter( "usercode ");
try{
File f=new File( "E:\\users ", "student.txt ");
FileReader in=new FileReader(f);
BufferedReader BufferIn=new BufferedReader(in);
String name= "ok ",code= "ok ";
while((name=BufferIn.readLine())!=null){
code=BufferIn.readLine();
out.print(name+ " <BR> ");
out.print(username+ " <BR> ");
out.print(code+ " <BR> ");
out.print(usercode+ " <BR> ");
if(username.equals(name)&&usercode.equals(code))
out.print( "Log In Successly ");
else
out.print( "Log In Failed ");
}
BufferIn.close();
in.close();
}catch(IOException ee){}%>
</form>
</body>
</html>
[解决办法]
if(username!=null && username.equals(name)&&usercode.equals(code))
[解决办法]
if(null!=username&&username.equals(name)&&null!=usercode&&usercode.equals(code))
我的异常网推荐解决方案：The server encountered an internal error () that prevented it from fulfilling this request.,http://www.myexception.cn/java-web/317.html
