杭电ACM多项式求和--》2011
#include <stdio.h>#include<iostream>using namespace std;int main(){ double sum=0; int n,m; scanf("%d",&n); while(n--) { scanf("%d",&m); for(int i=1;i<=m;i++) { if(i%2==0) sum=sum-1.0/i; else sum=sum+1.0/i; } printf("%.2f ",sum); } return 0;}