怎么获得jqgrid的editurl的返回值

如何获得jqgrid的editurl的返回值
本帖最后由 showbo 于 2012-08-03 16:26:01 编辑

jQuery().ready(function(){
        jQuery("#grid_id").jqGrid(
            {
              url:{url},
              datatype: "json",
              colNames:['A','B'],
              colModel:[
                        {name:'A',index:'a', editable:true},
                        {name:'B',index:'b', editable:true},
                       ],
              multiselect: true,
              rowNum:10,
              rownumbers:true,
              rowList:[10,20,30],
              pager: '#gridpager',
              sortname: 'a',
              viewrecords: true,
              sortorder: "asc",
              editurl:"test.php",
              height:220
            }
        );
       jQuery("#grid_id").jqGrid('navGrid','#gridpager',{edit:false,add:false,del:true});
       jQuery("#grid_id").jqGrid('inlineNav','#gridpager');
});