spring mvc +ExtJs FromPanel提交以后怎样跳转
我想通过spring mvc的方式来控制页面的跳转前台用extjs.
我的后台代码：
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import javax.servlet.http.HttpSession;
import org.springframework.stereotype.Controller;
import org.springframework.ui.ModelMap;
import org.springframework.web.bind.ServletRequestUtils;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.bind.annotation.RequestMethod;
@Controller
public class TestController {
@RequestMapping(value = "/test.htm", method = RequestMethod.POST)
public String test(HttpSession sesstion, HttpServletRequest request,
HttpServletResponse response, ModelMap map) {
//System.out.println("success");
try {
String username = ServletRequestUtils.getStringParameter(request,
"username");
//System.out.println(username);
map.addAttribute("username", username);
} catch (Exception e) {
e.printStackTrace();
}
return "portfolio/test";//这个是我要跳转的页面
}
}
前台Extjs代码：
Ext.onReady(function() {
Ext.loginForm = Ext.extend(Ext.form.FormPanel, {
xtype : "form",
title : "登錄",
labelWidth : 100,
labelAlign : "center",
buttonAlign : 'right',
layout : "form",
width : 400,
padding : "10px",
initComponent : function() {
this.items = [{
xtype : "textfield",
fieldLabel : "使用者名稱",
name : "username",
anchor : "95%"
}, {
xtype : "textfield",
fieldLabel : "密碼",
name : "password",
anchor : "95%",
inputType : "password"
}, {
xtype : "checkbox",
boxLabel : "記住登錄狀態",
name : "spring_security_remember_me",
anchor : "100%"
}]
this.buttons = [{
xtype : "button",
text : "登入",
type : "submit",
scope : this,
handler : function() {
this.getForm().doAction("submit", {
url : "/test.htm",//我要提交的处理的页面
scope : this,
success : function(form, action) {
alert("success");
},
failure : function(form, action) {
Ext.Msg
.alert(
'Warning!',
'Authentication server is unreachable : '
+ action.response.responseText);
}
})
}
}]
Ext.loginForm.superclass.initComponent.call(this);
}
})
var loginForm = new Ext.loginForm({
frame : true,
autoHeight : true,
renderTo : "login"
});
})
在Controler中我要返回什么且在Extjs的success模块怎么接收才能实现页面的跳转呢？
[解决办法]
spring里不需要指定跳转页面 那个是同步操作的时候才指定的
直接在后台将test方法改为void 函数中最后response写字符串结果就行
