求个JAVA小程序或者小游戏源代码和解析步骤，考试要用 谢谢了啊啊
考试需要我们做一个JAVA小程序，要求我们写下源代码并要求我们说出解析步骤，不要太难的那种，越简单越好，众大神求解救啊 多谢了
随便在书上找个带注释的弄懂就行了
[解决办法]
《面向对象程序设计》
题 目： 单间的井字棋小游戏
班 级： 通信104
学 号： 2010014271
姓 名： 张建腾
完成时间： 2011.10.27
1）应用意义
简单的娱乐小游戏 可以两人对战 富有趣味性
2）功能描述
上方两个按钮 选择阵营 点击方格落下棋子 当一方有三个棋子连成一线则获胜
3）结构分析
public class zjt extends JFrame {
/*首先设置参数*/
int x = 0, y = 0;
…..
/*主类zjt()： 实现面板 运行游戏 判断输赢 */
public zjt() {
Container c = getContentPane();
C.setLayout(new FlowLayout());
congxin = new JButton("重新开始红队先下");
c.add(congxin);
huanse = new JButton("重新开始蓝队先下");
c.add(huanse); // 添加两个按钮
jl=newJLabel(); // 按钮下的标签
c.add(jl, BorderLayout.SOUTH); //标签的位置
addMouseListener(new MouseAdapter() { //鼠标监听事件
public void mousePressed(MouseEvent event) {
if (event.isAltDown()) {
repaint();
} //按钮点击后开始画图调用repaint();方法 绘制棋子
x = event.getPoint().x; y = event.getPoint().y; int a = mm(x, y); //获取鼠标的X Y坐标
if (yin) {jl.setForeground(Color.RED);
jl.setText("游戏已结束,请重新开始");
} //赢了以后出现提示
else {
if (s[a] == 1) {jl.setForeground(Color.RED);
jl.setText(" 此位置有棋子,请另选位置重新下棋 ");
} // 判断有棋子的地方不能再下 并给出提示
else {
fa = false; if (a == 1) a1 = 1; ……………………………..
} /*若无棋子 鼠标点击后设置参数变为1*/
s[a] = 1;
}
});
congxin.addActionListener(new ActionListener() {
public void actionPerformed(ActionEvent arg0) {
for (int i = 0; i < s.length; i++) {
s[i] = 0;
jj[i] = 0;
}
……………………..
} /*点击按钮从新开始 并初始化 s[i] jj[i] 重新置零*/
/*画棋子 paint方法用于绘图 绘制出棋盘*/
public void paint(Graphics g) {
if (fa) {
super.paint(g);
int x = 100, y = 100, c = 300, k = 300;
for (int i = 0; i < 300; i += 100) //竖坐标每隔100画一条线
g.drawRect(x, y + i, c, k - i);
for (int i = 0; i < 300; i += 100 ) //很坐标每隔100画一条竖线
g.drawRect(x + i, y, c - i, k);
}
/*绘制红色的X棋子 并且该处参数变为1 每当其中一方下好一个后轮到对方下*/
else {
jl.setForeground(Color.black);
if (huatu) {
g.setColor(Color.red);
if (a1 == 1) {
g.drawLine(120, 120, 180, 180);
g.drawLine(180, 120, 120, 180);
a1 = 0;
jj[1] = 1;
}
……………………
}
huatu = false;
jl.setText("蓝队下棋");
}
/*绘制蓝方棋子 蓝色的O 绘制完成参数变为1 */
else {
g.setColor(Color.blue);
if (a1 == 1) {
g.drawOval(125, 125, 50, 50); //棋子O的位置大小
a1 = 0;
jj[1] = 2;
}
……………………………………
}
dd();
}
}
/*判断鼠标点击位置有没有在范围内 在的话参数由0变为1*/
public int mm(int x, int y) {
if (x >= 100 && x < 200 && y >= 100 && y < 200)
a = 1;
else if (x >= 200 && x < 300 && y >= 100 && y < 200)
a = 2;
……………………..
else
a = 0;
return a;
}
/*判断输赢、有连着的三个部分为相同则获胜否则都不获胜 并给出提示*/
public void dd() {
if (jj[1] == 1 && jj[2] == 1 && jj[3] == 1) {
jl.setForeground(Color.RED);
jl.setText("红方获胜,连接线1,2,3");
yin = true;
}
………………………………. }
[解决办法]
4）实现结果
5）源代码
mport java.awt.BorderLayout;
import java.awt.Color;
import java.awt.Container;
import java.awt.FlowLayout;
import java.awt.Graphics;
import java.awt.event.ActionEvent;
import java.awt.event.ActionListener;
import java.awt.event.MouseAdapter;
import java.awt.event.MouseEvent;
import javax.swing.JButton;
import javax.swing.JFrame;
import javax.swing.JLabel;
public class zjt extends JFrame {
int x = 0, y = 0;
int a = 0;
int x1 = 0, y1 = 0, x2 = 0, y2 = 0, x3 = 0, y3 = 0, x4 = 0, y4 = 0;;
boolean fa = true, huatu = true, yin = false;
int a1 = 0, a2 = 0, a3 = 0, a4 = 0, a5 = 0, a6 = 0, a7 = 0, a8 = 0, a9 = 0;
int s[] = new int[10], jj[] = new int[10];
JButton congxin, huanse;
JLabel jl;
public zjt() {
Container c = getContentPane();
c.setLayout(new FlowLayout());
congxin = new JButton("重新开始红队先下");
c.add(congxin);
huanse = new JButton("重新开始蓝队先下");
c.add(huanse);
jl = new JLabel();
c.add(jl, BorderLayout.SOUTH);
addMouseListener(new MouseAdapter() {
public void mousePressed(MouseEvent event) {
if (event.isAltDown()) {
repaint();
}
x = event.getPoint().x;
y = event.getPoint().y;
int a = mm(x, y);
if (yin) {
jl.setForeground(Color.RED);
jl
.setText("游戏已结束,请重新开始");
}
else {
if (s[a] == 1) {
jl.setForeground(Color.RED);
jl.setText(" 此位置有棋子,请另选位置重新下棋 ");
}
else {
fa = false;
if (a == 1)
a1 = 1;
if (a == 2)
a2 = 1;
if (a == 3)
a3 = 1;
if (a == 4)
a4 = 1;
if (a == 5)
a5 = 1;
if (a == 6)
a6 = 1;
if (a == 7)
a7 = 1;
if (a == 8)
a8 = 1;
if (a == 9)
a9 = 1;
jl.setText("");
repaint();
}
}
s[a] = 1;
}
});
congxin.addActionListener(new ActionListener() {
public void actionPerformed(ActionEvent arg0) {
for (int i = 0; i < s.length; i++) {
s[i] = 0;
jj[i] = 0;
}
fa = true;
repaint();
yin = false;
huatu = true;
jl.setForeground(Color.black);
jl.setText("红队先下");
}
});
huanse.addActionListener(new ActionListener() {
public void actionPerformed(ActionEvent arg0) {
for (int i = 0; i < s.length; i++) {
s[i] = 0;
jj[i] = 0;
}
fa = true;
repaint();
yin = false;
huatu = false;
jl.setForeground(Color.black);
jl
.setText("蓝队先下");
}
});
setSize(500, 500);
setVisible(true);
}
public void paint(Graphics g) {
if (fa) {
super.paint(g);
int x = 100, y = 100, c = 300, k = 300;
for (int i = 0; i < 300; i += 100)
g.drawRect(x, y + i, c, k - i);
for (int i = 0; i < 300; i += 100)
g.drawRect(x + i, y, c - i, k);
}
else {
jl.setForeground(Color.black);
if (huatu) {
g.setColor(Color.red);
if (a1 == 1) {
g.drawLine(120, 120, 180, 180);
g.drawLine(180, 120, 120, 180);
a1 = 0;
jj[1] = 1;
}
if (a2 == 1) {
g.drawLine(220, 120, 280, 180);
g.drawLine(280, 120, 220, 180);
a2 = 0;
jj[2] = 1;
}
if (a3 == 1) {
g.drawLine(320, 120, 380, 180);
g.drawLine(380, 120, 320, 180);
a3 = 0;
jj[3] = 1;
}
if (a4 == 1) {
g.drawLine(120, 220, 180, 280);
g.drawLine(180, 220, 120, 280);
a4 = 0;
jj[4] = 1;
}
if (a5 == 1) {
g.drawLine(220, 220, 280, 280);
g.drawLine(280, 220, 220, 280);
a5 = 0;
jj[5] = 1;
}
if (a6 == 1) {
g.drawLine(320, 220, 380, 280);
g.drawLine(380, 220, 320, 280);
a6 = 0;
jj[6] = 1;
}
if (a7 == 1) {
g.drawLine(120, 320, 180, 380);
g.drawLine(180, 320, 120, 380);
a7 = 0;
jj[7] = 1;
}
if (a8 == 1) {
g.drawLine(220, 320, 280, 380);
g.drawLine(280, 320, 220, 380);
a8 = 0;
jj[8] = 1;
}
if (a9 == 1) {
g.drawLine(320, 320, 380, 380);
g.drawLine(380, 320, 320, 380);
a9 = 0;
jj[9] = 1;
}
huatu = false;
jl.setText("蓝队下棋");
} else {
g.setColor(Color.blue);
if (a1 == 1) {
g.drawOval(125, 125, 50, 50);
a1 = 0;
jj[1] = 2;
}
if (a2 == 1) {
g.drawOval(225, 125, 50, 50);
a2 = 0;
jj[2] = 2;
}
if (a3 == 1) {
g.drawOval(325, 125, 50, 50);
a3 = 0;
jj[3] = 2;
}
if (a4 == 1) {
g.drawOval(125, 225, 50, 50);
a4 = 0;
jj[4] = 2;
}
if (a5 == 1) {
g.drawOval(225, 225, 50, 50);
a5 = 0;
jj[5] = 2;
}
if (a6 == 1) {
g.drawOval(325, 225, 50, 50);
a6 = 0;
jj[6] = 2;
}
if (a7 == 1) {
g.drawOval(125, 325, 50, 50);
a7 = 0;
jj[7] = 2;
}
if (a8 == 1) {
g.drawOval(225, 325, 50, 50);
a8 = 0;
jj[8] = 2;
}
if (a9 == 1) {
g.drawOval(325, 325, 50, 50);
a9 = 0;
jj[9] = 2;
}
huatu = true;
jl.setText("红队下棋");
}
dd();
}
}
public int mm(int x, int y) {
if (x >= 100 && x < 200 && y >= 100 && y < 200)
a = 1;
else if (x >= 200 && x < 300 && y >= 100 && y < 200)
a = 2;
else if (x >= 300 && x < 400 && y >= 100 && y < 200)
a = 3;
else if (x >= 100 && x < 200 && y >= 200 && y < 300)
a = 4;
else if (x >= 200 && x < 300 && y >= 200 && y < 300)
a = 5;
else if (x >= 300 && x < 400 && y >= 200 && y < 300)
a = 6;
else if (x >= 100 && x < 200 && y >= 300 && y < 400)
a = 7;
else if (x >= 200 && x < 300 && y >= 300 && y < 400)
a = 8;
else if (x >= 300 && x < 400 && y >= 300 && y < 400)
a = 9;
else
a = 0;
return a;
}
public void dd() {
if (jj[1] == 1 && jj[2] == 1 && jj[3] == 1) {
jl.setForeground(Color.RED);
jl.setText("红方获胜,连接线1,2,3");
yin = true;
}
if (jj[4] == 1 && jj[5] == 1 && jj[6] == 1) {
jl.setForeground(Color.RED);
jl
.setText("红方获胜,连接线4,5,6");
yin = true;
}
if (jj[7] == 1 && jj[8] == 1 && jj[9] == 1) {
jl.setForeground(Color.RED);
jl.setText("红方获胜,连接线7,8,9");
yin = true;
}
if (jj[1] == 1 && jj[5] == 1 && jj[9] == 1) {
jl.setForeground(Color.RED);
jl.setText("红方获获胜,连接线1,5,9");
yin = true;
}
if (jj[3] == 1 && jj[5] == 1 && jj[7] == 1) {
jl.setForeground(Color.RED);
jl.setText("红方获胜,连接线3,5,7");
yin = true;
}
if (jj[1] == 1 && jj[4] == 1 && jj[7] == 1) {
jl.setForeground(Color.RED);
jl.setText("红方获胜,连接线1,4,7");
yin = true;
}
if (jj[2] == 1 && jj[5] == 1 && jj[8] == 1) {
jl.setForeground(Color.RED);
jl.setText("红方获胜,连接线2,5,8");
yin = true;
}
if (jj[3] == 1 && jj[6] == 1 && jj[9] == 1) {
jl.setForeground(Color.RED);
jl.setText("红方获胜,连接线3,6,9");
yin = true;
}
if (jj[1] == 2 && jj[2] == 2 && jj[3] == 2) {
jl.setForeground(Color.RED);
jl.setText("蓝方获胜,连接线1,2,3");
yin = true;
}
if (jj[4] == 2 && jj[5] == 2 && jj[6] == 2) {
jl.setForeground(Color.RED);
jl.setText("蓝方获胜,连接线4,5,6");
yin = true;
}
if (jj[7] == 2 && jj[8] == 2 && jj[9] == 2) {
jl.setForeground(Color.RED);
jl.setText("蓝方获胜,连接线7,8,9");
yin = true;
}
if (jj[1] == 2 && jj[5] == 2 && jj[9] == 2) {
jl.setForeground(Color.RED);
jl.setText(" 蓝方获胜,连接线1,5,9 ");
yin = true;
}
if (jj[3] == 2 && jj[5] == 2 && jj[7] == 2) {
jl.setForeground(Color.RED);
jl.setText("蓝方获胜,连接线3,5,7 ");
yin = true;
}
if (jj[1] == 2 && jj[4] == 2 && jj[7] == 2) {
jl.setForeground(Color.RED);
jl.setText("蓝方获胜,连接线1,4,7 ");
yin = true;
}
if (jj[2] == 2 && jj[5] == 2 && jj[8] == 2) {
jl.setForeground(Color.RED);
jl.setText("蓝方获胜,连接线2,5,8");
yin = true;
}
if (jj[3] == 2 && jj[6] == 2 && jj[9] == 2) {
jl.setForeground(Color.RED);
jl.setText("蓝方获胜,连接线3,6,9");
yin = true;
}
if (s[1] == 1 && s[2] == 1 && s[3] == 1 && s[4] == 1 && s[5] == 1
&& s[6] == 1 && s[7] == 1 && s[8] == 1 && s[9] == 1) {
jl.setForeground(Color.RED);
jl.setText("双方都没获胜,游戏结束");
yin = true;
}
System.out.println(jj[2]);
}
public static void main(String[] args) {
zjt s = new zjt();
s.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
}
}
6）设计总结
通过自己设计小程序 更加深刻的理解了书本上的知识
自己设计自己调试 找到错误试着解决 或者请教别人 都对知识的巩固和运用有很大帮助
并且通过网络 自学了一些书上没有的知识 比如java中的paint方法 用来绘制图形 以此类推 五子棋围棋的棋盘都可以绘制了
