在线等待高手解答,latch: cache buffers chains事件怎么解决!
1SQL_ID 6s7jtnzrmmuw1, child number 0
2-------------------------------------
3insert /*+ append */ into qianyi.WEB_APP_BASE select * from V_WEB_APP_BASE
4
5Plan hash value: 843235207
6
7------------------------------------------------------------------------
8| Id | Operation | Name | Rows | Bytes |TempSpc| Cost (%CPU)| Time |
9------------------------------------------------------------------------
10| 0 | INSERT STATEMENT | | | | | 16714 (100)| |
11| 1 | LOAD AS SELECT | | | | | | |
12| 2 | VIEW | V_WEB_APP_BASE | 50001 | 1035M| | 16714 (2)| 00:01:54 |
13| 3 | UNION-ALL | | | | | | |
14| 4 | NESTED LOOPS | | 1 | 707 | | 4 (0)| 00:00:01 |
15| 5 | TABLE ACCESS FULL | T_PLY_BASE_TRANS | 1 | 38 | | 2 (0)| 00:00:01 |
16| 6 | TABLE ACCESS BY INDEX ROWID| T_PLY_BASE | 1 | 669 | | 2 (0)| 00:00:01 |
17|* 7 | INDEX UNIQUE SCAN | PK_PLY_BASE | 1 | | | 1 (0)| 00:00:01 |
18|* 8 | HASH JOIN | | 50000 | 56M| 2056K| 16710 (2)| 00:01:54 |
19| 9 | TABLE ACCESS FULL | T_EDR_BASE_TRANS | 50000 | 1464K| | 61 (4)| 00:00:01 |
20| 10 | TABLE ACCESS FULL | T_EDR_BASE | 509K| 562M| | 8213 (3)| 00:00:56 |
21------------------------------------------------------------------------
22
23Predicate Information (identified by operation id):
24---------------------------------------------------
25
26 7 - access("A"."C_PLY_APP_NO"="B"."C_PLY_APP_NO")
27 8 - access("C"."C_EDR_APP_NO"="D"."C_EDR_APP_NO")
28