MySql语句效率问题
people 表有id 和 name，id是主键，自动增加。
我想从id最后一个往前只搜索 n 行(n<count(*))，并找到满足条件的，如果 n行里没有找到就不继续往下找。
本来想用：select * from people where name="xxx" order by id desc limit 1000;
可我发现 limit 1000并不是只搜索1000行，而是显示满足条件的1000行。
如果写成 select * from people where id>((select count(id))-1000) order by id desc limit 1;这样效率肯定很低。
那么我就改成 select * from people where id > ((select id from people order by id desc limit 1)-1000) order by id
desc limit 1;
请问这样效率如何？有更好方法否？
[解决办法]
select *
from tb
where id>(select max(id)-1000 from tb)
limit n;
[解决办法]
select * from people a inner join
(select id from people order by id desc limit 1)-1000) b
on a.id>b.id
order by a.id desc limit 1;
