求助~~~ g++ 编译器的疑问,vc++能通过，g++报错。。。。
g++编译器是不是不允许把类型参数传给vector呢？
具体情况如下，定义一个模版函数:
template <typename Iterator, typename ElemType>
vector<ElemType> sub_vec(const Iterator first, const Iterator last, const ElemType &val)
{
vector<ElemType> vec(first, last);
sort(vec.begin(), vec.end());
vector<ElemType>::iterator it = find_if(vec.begin(), vec.end(), bind2nd(greater<ElemType>(), val));
vec.erase(vec.begin(), it);
return vec;
}
用类型参数直接定义vector<ElemType>，g++就会报错，但可以在vc编译器可下通过
g++的错误信息
as.cpp: In function `std::vector<ElemType, std::allocator<_T2> > sub_vec(Iterator, Iterator, const ElemType&)':
as.cpp:22: error: expected `;' before "it"
as.cpp:23: error: `it' was not declared in this scope
as.cpp: In function `std::vector<ElemType, std::allocator<_T2> > sub_vec(Iterator, Iterator, const ElemType&) [with Iterator = __gnu_cx
x::__normal_iterator<int*, std::vector<int, std::allocator<int> > >, ElemType = int]':
as.cpp:52: instantiated from here
as.cpp:22: error: dependent-name ` std::vector<ElemType,std::allocator<_T2> >::iterator' is parsed as a non-type, but instantiation yie
lds a type
as.cpp:22: note: say `typename std::vector<ElemType,std::allocator<_T2> >::iterator' if a type is meant
[解决办法]
唉，基础不过关啊
