python 如何得到匹配到string的行
文件名:change.log
我想匹配到error并返回行.
类似于grep error change.log
用python如何实现？
change.log 文件内容
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用perl实现如下：
#!/usr/bin/perl -w
open(F1,"change.log"||die "Cannot open change.log!";
my @grp=<F1>;
foreach my $va(@grp) {
? ? ? ? #print $va;
if ($va=~/error/i) {
? ? ? ? print "$va\n";
}
}
python怎么匹配？
?
?
?
1.
print ''.join([x for x in open('change.log').readlines() if x.find('error')!=-1])
?
2.
print (''.join([x for x in open('change.log').readlines() if re.search('error',x)]))
?
3.忽略大小写
转换成小写或大写来判断就等于忽略大小写了
print( "".join([x for x in open('change.log').readlines() if x.lower().find('error')!=-1]))
print( "".join([x for x in open('change.log').readlines() if x.upper().find('ERROR')!=-1]))
?
正则
print (''.join([x for x in open('change.log').readlines() if re.search('error',x,re.I)]))
?
?
1.
#!/usr/bin/python
a=open("change.log").readlines()
for x in a:
?if x.find("error") != -1:
??print(x)
?
2.
#!/usr/bin/python
import re
a=open("change.log").readlines()
#print(a)
for x in a:
?#print(x)
?if re.search("error",x,re.I):
??print(x,end="")
?
?
http://bbs.chinaunix.net/thread-3729007-1-1.html
