汇编语言写的一个电子时钟。有个问题
[code=Assembly][/code]
assume cs:code
code segment
start:mov ax,0b800h
mov es,ax
mov di,0
mov ax,0
mov cx,2000
clr:mov es:[di],ax
add di,2
loop clr
time:mov al,9
out 70h,al
in al,71h
mov ah,al
mov cl,4
shr ah,cl
and al,00001111b
add ah,30h
add al,30h
mov bx,0b800h
mov es,bx
mov byte ptr es:[160*10+30*2],ah
mov byte ptr es:[160*10+30*2+2],al
mov al,'/'
mov byte ptr es:[160*10+30*2+4],al
mov al,8
out 70h,al
in al,71h
mov ah,al
mov cl,4
shr ah,cl
and al,00001111b
add ah,30h
add al,30h
mov byte ptr es:[160*10+30*2+6],ah
mov byte ptr es:[160*10+30*2+8],al
mov al,'/'
mov byte ptr es:[160*10+30*2+10],al
mov al,7
out 70h,al
in al,71h
mov ah,al
mov cl,4
shr ah,cl
and al,00001111b
add ah,30h
add al,30h
mov byte ptr es:[160*10+30*2+12],ah
mov byte ptr es:[160*10+30*2+14],al
mov al,' '
mov byte ptr es:[160*10+30*2+16],al
mov al,4
out 70h,al
in al,71h
mov ah,al
mov cl,4
shr ah,cl
and al,00001111b
add ah,30h
add al,30h
mov byte ptr es:[160*10+30*2+18],ah
mov byte ptr es:[160*10+30*2+20],al
mov al,':'
mov byte ptr es:[160*10+30*2+22],al
mov al,2
out 70h,al
in al,71h
mov ah,al
mov cl,4
shr ah,cl
and al,00001111b
add ah,30h
add al,30h
mov byte ptr es:[160*10+30*2+24],ah
mov byte ptr es:[160*10+30*2+26],al
mov al,':'
mov byte ptr es:[160*10+30*2+28],al
mov al,0
out 70h,al
in al,71h
mov ah,al
mov cl,4
shr ah,cl
and al,00001111b
add ah,30h
add al,30h
mov byte ptr es:[160*10+30*2+30],ah
mov byte ptr es:[160*10+30*2+32],al
mov al,00001110b
mov di,1
mov cx,17
color:mov es:[160*10+30*2+di],al
inc di
inc di
loop color
jmp far ptr time
mov ax,4c00h
int 21h
code ends
end start
发现CPU使用率相当高。谁有好办法
[解决办法]
链到INT 1Ch中
