J2me 游戏点阵字库引擎（五）之部分汉字库
????? 最近有点忙，现在到今天才有时间继续我的博文！
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1. 对于现流行的J2ME游戏开发而言，有美术、策划和程序。图片由美术完成，游戏控制脚本由策划撰写，实现是由程序负责编写。在三个分工中，会出现汉字部分就是程序(操作说明)，还有脚本(人物对话和场景说明)。为此我们需要编写一个程序将游戏的代码部分和脚本过滤出来。在下面的代码中，我采用扩展名来标识:
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// 筛选出指定扩展名的文件public String[] filterFile(String directory, String[] extendFileName) {LinkedList<String> allFilePath = new LinkedList<String>();LinkedList<String> allFilterFilePath = new LinkedList<String>();searchFile(directory, allFilePath);for (int i = 0, size = allFilePath.size(); i < size; i++) {String path = allFilePath.get(i);if (getFileCodeFormate(path, extendFileName) != -1) {allFilterFilePath.add(path);}}String[] pathStr = new String[allFilterFilePath.size()];allFilterFilePath.toArray(pathStr);return pathStr;}// 查找出全部的文件public void searchFile(String directory, LinkedList<String> linkedList) {File file = new File(directory);if (file.isFile()) {linkedList.add(directory);} else {String[] subFiles = file.list();for (int i = 0; i < subFiles.length; i++) {searchFile(directory + "/" + subFiles[i], linkedList);}}}?
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? 运行结果如图:
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2.将文件中汉字提前出来，并作重复性校验 代码如下：
//读取全部文件的内容public String getAllFileFont(String[] allFilePath, String[] extendFileName, String[] fileFormate) {String[] oneFileFont = new String[allFilePath.length];int tem;String allfileFont = "";for (int i = 0, len = oneFileFont.length; i < len; i++) {tem = getFileCodeFormate(allFilePath[i], extendFileName);oneFileFont[i] = getTextByFormate(allFilePath[i], fileFormate[tem]);oneFileFont[i] = getSoleWord(oneFileFont[i]);}for (int i = 0; i < allFilePath.length; i++) {allfileFont = oneFileFont[i] + allfileFont;}allfileFont = getSoleWord(allfileFont);return allfileFont; }// 由扩展名 得出对于的格式public int getFileCodeFormate(String path, String[] extendFileName) {if (extendFileName == null || extendFileName.length == 0) {return -1;} else {for (int i = 0, len = extendFileName.length; i < len; i++) {if ("".equals(extendFileName[i].trim())&& path.indexOf(".") == -1) {return i;} else if (!"".equals(extendFileName[i].trim())&& path.endsWith(extendFileName[i])) {return i;}}return -1;}}//将对应文件的扩展名应相应的格式读取出来。private String getTextByFormate(String name, String formate) {String strReturn = "";int ic;ByteArrayOutputStream baos = new ByteArrayOutputStream();DataOutputStream dos = new DataOutputStream(baos);FileInputStream fileInputStream;byte[] myData;byte[] buffer = new byte[1024];try {fileInputStream = new FileInputStream(new File(name));if (fileInputStream != null) {while ((ic = fileInputStream.read(buffer)) > 0) {dos.write(buffer, 0, ic);}myData = baos.toByteArray();// // ANSI： 无格式定义；// // Unicode： 前两个字节为FFFE；// // Unicode big endian： 前两字节为FEFF； // // UTF-8： 前两字节为EFBB； // if ((myData[0] ^ (byte) 0xFE) == 0// && (myData[1] ^ (byte) 0xFF) == 0) {// formate = "Unicode";// } else if ((myData[0] ^ (byte) 0xFF) == 0// && (myData[1] ^ (byte) 0xFE) == 0) {// formate = " Unicode big endian";// } else if ((myData[0] ^ (byte) 0xEF) == 0// && (myData[1] ^ (byte) 0xBB) == 0) {// formate = "UTF-8";// } else {// formate = "GBK";// }strReturn = new String(myData, formate);fileInputStream.close();}dos.close();baos.close();} catch (Exception e) {System.out.println("getTextByUTF Error:" + e.toString());} finally {myData = null;buffer = null;fileInputStream = null;dos = null;baos = null;}System.gc();return strReturn;}//进行不重复性校验private String getSoleWord(String str) {HashSet<String> ts = new HashSet();for (int i = 0; i < str.length(); i++) {String subStr = str.substring(i, i + 1);ts.add(subStr);}Iterator<String> entry = ts.iterator();StringBuffer sb = new StringBuffer();for (; entry.hasNext();) {sb.append((String) entry.next());}String ret = sb.toString();return ret;}??
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运行结果如图：
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?3.此时我得到的只是汉字的机内码，现在我们将其排序一下，其作用以后再分析？？
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//按机内码对字符串进行排序private String sortAsCodeSequence(String str) {int len = str.length();int codeSequence[] = new int[len];for (int i = 0; i < len; i++) {codeSequence[i] = str.charAt(i);}Arrays.sort(codeSequence);StringBuffer sb = new StringBuffer();for (int i = 0; i < len; i++) {sb.append((char) (codeSequence[i]));}return sb.toString();}?
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