去掉文字，从小到大排列，等待高手！该如何解决

去掉文字，从小到大排列，等待高手！！！！！！！！
文件out.txt中，有如下内容：

出现1次的号码5注:
533 574 575 735 773  

出现2次的号码6注:
333 373 554 573 733 755  

出现3次的号码3注:
473 484 775  

要求：
编写程序，从out.txt中读取内容，经过处理后，显示
效果如下：

出现1次的号码14注:
333 373 473 484 533 554 573 574 575 733
735 755 773 775


[解决办法]
文件data.txt

JScript code

出现1次的号码5注:533 574 575 735 773   出现2次的号码6注:333 373 554 573 733 755   出现3次的号码3注:473 484 775
[解决办法]
Java code
import java.util.ArrayList;import java.util.Collections;import java.util.List;import java.util.regex.Matcher;import java.util.regex.Pattern;public class NumberSort {    static String s;    // 模拟文件读取    static {        s = "出现1次的号码5注:\r\n";        s += "533 574 575 735 773\r\n";        s += "\r\n";        s += "出现2次的号码6注:\r\n";        s += "333 373 554 573 733 755\r\n";        s += "\r\n";        s += "出现3次的号码3注:\r\n";        s += "473 484 775\r\n";    }    public static void main(String[] args) {        List<Integer> list = new ArrayList<Integer>();        // 通过正则找出三位数的数组放进list中        Matcher m = Pattern.compile("\\d{3}").matcher(s);        while (m.find()) {            list.add(new Integer(m.group()));        }        // 给list排序        Collections.sort(list);        StringBuilder sb = new StringBuilder();        System.out.println("出现1次的号码" + list.size() + "注:");        for (int i = 0; i < list.size(); i++) {            sb.append(list.get(i)).append(" ");            if ((i + 1) % 10 == 0) {                sb.append("\r\n");            }        }        // 结果        String result = sb.toString().trim();        System.out.println(result);    }}
[解决办法]
Java code
public static void main(String[] args) throws IOException {        File file = new File("file.txt");        BufferedReader br = new BufferedReader(new FileReader(file));        List<Integer> numbers = new ArrayList();        StringBuffer str = new StringBuffer();        String temp ;        while((temp = br.readLine()) != null){            str.append(temp);        }        br.close();        Pattern pattern = Pattern.compile("\\d{3}");        Matcher matcher = pattern.matcher(str.toString());        while(matcher.find()){            numbers.add(Integer.parseInt(matcher.group()));        }        Collections.sort(numbers);        for (int i = 0; i < numbers.size(); i++) {            System.out.print(numbers.get(i) + "\t");            if( i != 0 && i % 10 == 0)System.out.println();        }    }
[解决办法]
Java code
    public static void main(String[] args) throws IOException {        File file = new File("file.txt");        BufferedReader br = new BufferedReader(new FileReader(file));        List<Integer> numbers = new ArrayList();        StringBuffer str = new StringBuffer();        String temp ;        while((temp = br.readLine()) != null){            str.append(temp);        }        br.close();        Pattern pattern = Pattern.compile("\\d{3}");        Matcher matcher = pattern.matcher(str.toString());        while(matcher.find()){            numbers.add(Integer.parseInt(matcher.group()));        }        Collections.sort(numbers);        System.out.println("出现一次的号码为：" + numbers.size() + "注");        for (int i = 0; i < numbers.size(); i++) {            System.out.print(numbers.get(i) + "\t");            if((i + 1) % 10 == 0)System.out.println();        }            }