(高分)求一个万年历的算法。输入年,就可输出该年的年历
求一个万年历的算法。输入年,就可输出该年的年历
[解决办法]
现在网上有不少万年历的网页，大部分是jsp写的，你查看它的源码就清楚了。大意是将每年阴历月份的信息记录在一个数组内。然后按图索骥……关键是这组数据。我这有一组现成的：
var lunarInfo=new Array(
0x04bd8,0x04ae0,0x0a570,0x054d5,0x0d260,0x0d950,0x16554,0x056a0,0x09ad0,0x055d2,
0x04ae0,0x0a5b6,0x0a4d0,0x0d250,0x1d255,0x0b540,0x0d6a0,0x0ada2,0x095b0,0x14977,
0x04970,0x0a4b0,0x0b4b5,0x06a50,0x06d40,0x1ab54,0x02b60,0x09570,0x052f2,0x04970,
0x06566,0x0d4a0,0x0ea50,0x06e95,0x05ad0,0x02b60,0x186e3,0x092e0,0x1c8d7,0x0c950,
0x0d4a0,0x1d8a6,0x0b550,0x056a0,0x1a5b4,0x025d0,0x092d0,0x0d2b2,0x0a950,0x0b557,
0x06ca0,0x0b550,0x15355,0x04da0,0x0a5d0,0x14573,0x052d0,0x0a9a8,0x0e950,0x06aa0,
0x0aea6,0x0ab50,0x04b60,0x0aae4,0x0a570,0x05260,0x0f263,0x0d950,0x05b57,0x056a0,
0x096d0,0x04dd5,0x04ad0,0x0a4d0,0x0d4d4,0x0d250,0x0d558,0x0b540,0x0b5a0,0x195a6,
0x095b0,0x049b0,0x0a974,0x0a4b0,0x0b27a,0x06a50,0x06d40,0x0af46,0x0ab60,0x09570,
0x04af5,0x04970,0x064b0,0x074a3,0x0ea50,0x06b58,0x055c0,0x0ab60,0x096d5,0x092e0,
0x0c960,0x0d954,0x0d4a0,0x0da50,0x07552,0x056a0,0x0abb7,0x025d0,0x092d0,0x0cab5,
0x0a950,0x0b4a0,0x0baa4,0x0ad50,0x055d9,0x04ba0,0x0a5b0,0x15176,0x052b0,0x0a930,
0x07954,0x06aa0,0x0ad50,0x05b52,0x04b60,0x0a6e6,0x0a4e0,0x0d260,0x0ea65,0x0d530,
0x05aa0,0x076a3,0x096d0,0x04bd7,0x04ad0,0x0a4d0,0x1d0b6,0x0d250,0x0d520,0x0dd45,
0x0b5a0,0x056d0,0x055b2,0x049b0,0x0a577,0x0a4b0,0x0aa50,0x1b255,0x06d20,0x0ada0)
提取信息的算法有：
function lYearDays(y) {
var i, sum = 348
for(i=0x8000; i> 0x8; i> > =1) sum += (lunarInfo[y-1900] & i)? 1: 0
return(sum+leapDays(y))
}
function leapDays(y) {
if(leapMonth(y)) return((lunarInfo[y-1900] & 0x10000)? 30: 29)
else return(0)
}
function leapMonth(y) {
return(lunarInfo[y-1900] & 0xf)
}
function monthDays(y,m) {
return( (lunarInfo[y-1900] & (0x10000> > m))? 30: 29 )
}
明白了吧？
[解决办法]
//====================================== 传回农历 y年的总天数
function lYearDays(y) {
var i, sum = 348
for(i=0x8000; i> 0x8; i> > =1) sum += (lunarInfo[y-1900] & i)? 1: 0
return(sum+leapDays(y))
}
//====================================== 传回农历 y年闰月的天数
function leapDays(y) {
if(leapMonth(y)) return((lunarInfo[y-1900] & 0x10000)? 30: 29)
else return(0)
}
//====================================== 传回农历 y年闰哪个月 1-12 , 没闰传回 0
function leapMonth(y) {
return(lunarInfo[y-1900] & 0xf)
}
//====================================== 传回农历 y年m月的总天数
function monthDays(y,m) {
return( (lunarInfo[y-1900] & (0x10000> > m))? 30: 29 )
}
数组中每个数字表示1年，第一个数字0x04bd8代表1900年。
每个数字16bit，前12bit表示每月是否大月，1表示大月，30天，0表示小月，29天。最后4个bit表示是否有闰月和闰哪个月
