为什么sscanf会改变ph的值，太离奇了！解决方案

为什么sscanf会改变ph的值，太离奇了！
一个简单的C程序，在winodws和linux上都测试过了。发现结果非常离奇：sscanf改变了ph的值，到底是为什么呢？

C/C++ code

#include <stdio.h>int main(){    int i = 0;    char ph[] = "015865478569";    unsigned char bcd[6];    printf("1. ph = [%s]\n", ph);    sscanf(ph, "%02x%02x%02x%02x%02x%02x", &bcd[0], &bcd[1], &bcd[2], &bcd[3], &bcd[4], &bcd[5]);    //sscanf(ph, "%2x%2x%2x%2x%2x%2x", &bcd[0], &bcd[1], &bcd[2], &bcd[3], &bcd[4], &bcd[5]);    printf("2. ph = [%s]\n", ph);    // ?为什么ph为空了？？    for(i = 0; i < 6; i++)        printf("%02x ", bcd[i]);    puts("\n");    return 0;}

C/C++ code

#include <stdio.h>int main(){    int i = 0;    char ph2[] = "015865478569";    char ph[] = "015865478569";    char ph1[] = "015865478569";    unsigned char bcd[6];    printf("1. ph = [%s]\n", ph);    //sscanf(ph, "%02x%02x", &bcd[0], &bcd[1]);    sscanf(ph, "%02x%02x%02x%02x%02x%02x", &bcd[0], &bcd[1], &bcd[2], &bcd[3], &bcd[4], &bcd[5]);    //sscanf(ph, "%2x%2x%2x%2x%2x%2x", &bcd[0], &bcd[1], &bcd[2], &bcd[3], &bcd[4], &bcd[5]);    printf("2. ph = [%s]\n", ph);    // ?为什么ph为空了？？    for(i = 0; i < 6; i++)        printf("%02x ", bcd[i]);    puts("\n");    return 0;}
[解决办法]
不会吧  我运行了一下，
结果输出啊 ！！
1. ph = [015865478569]
2. ph = [015865478569]
01 58 65 47 85 69
[解决办法]
自己转换，每半字节存一个，只能0~F