输入某年某月某日,判断这一天是这一年的第几天?
输入某年某月某日,判断这一天是这一年的第几天?
[解决办法]
main()
{
int day,month,year,sum,leap;
printf( "\nplease input year,month,day\n ");
scanf( "%d,%d,%d ",&year,&month,&day);
switch(month)/*先计算某月以前月份的总天数*/
{
case 1:sum=0;break;
case 2:sum=31;break;
case 3:sum=59;break;
case 4:sum=90;break;
case 5:sum=120;break;
case 6:sum=151;break;
case 7:sum=181;break;
case 8:sum=212;break;
case 9:sum=243;break;
case 10:sum=273;break;
case 11:sum=304;break;
case 12:sum=334;break;
default:printf( "data error ");break;
}
sum=sum+day; /*再加上某天的天数*/
if(year%400==0||(year%4==0&&year%100!=0))/*判断是不是闰年*/
leap=1;
else
leap=0;
if(leap==1&&month> 2)/*如果是闰年且月份大于2,总天数应该加一天*/
sum++;
printf( "It is the %dth day. ",sum);}
[解决办法]
请楼主参考:
main()
{
int y,m,d,f,t,n;
printf( "y,m,d=: ");
scanf( "%d,%d,%d ",&y,&m,&d);
f=(y%4==0 && y%100!=0 || y%400==0);
if(m <1 || m> 12) exit(0);
t=31-((m==4)+(m==6)+(m==9)+(m==11))-(3-f)*(m==2);
if(d <1 || d> t) exit(0);
n=d+31*((m> 1)+(m> 3)+(m> 5)+(m> 7)+(m> 8)+(m> 10))+30*((m> 4)+(m> 6)+(m> 9)+(m> 11))+(28+f)*(m> 2);
printf( "n=%d\n ",n);
}