mysql关联查询语句如何写?
数据库:mysql
表A字段:id bides(存储值为 1,2,3,4,5,6...)
表B字段: id name
现在只知道A表中的ID值,请问如何循环列出A表该ID值对应的 B表集合!
也就是说给一个A表ID,然后列出B表中的内容(B表内容为:A表bides字段中的值)?????
[解决办法]
SELECT * FROM A,B
where B.IdA.bides and A.id=1
order by B.id desc
[解决办法]
mysql> select * from a;+------+----------+| id | BIdes |+------+----------+| 1 | 1,3,4,5 || 2 | 2,4,8,10 |+------+----------+2 rows in set (0.00 sec)mysql> select * from b;+------+------+| id | name |+------+------+| 1 | A || 2 | B || 3 | C || 4 | D || 5 | E |+------+------+5 rows in set (0.00 sec)mysql> select b.* -> from A,b -> where a.id=1 And find_in_set(B.id,a.BIdes);+------+------+| id | name |+------+------+| 1 | A || 3 | C || 4 | D || 5 | E |+------+------+4 rows in set (0.02 sec)mysql>
[解决办法]
用你的数据:
select b.* from b left join b on instr(a.BIdes,B.id)>0 where a.id=1