【100分，确实有些疑难】关于按照某个字段部分内容来进行Group By的问题。
我要做个电子邮件发送统计
表的数据如下:
Mail_From | Mail_To
----------------------------------------------------
liming |aa@sina.com;bb@sina.com;mmm@yahoo.com.cn
liming |aa@sina.com
liming |bb@sina.com
liming |baby@hotmail.com;mmm@yahoo.com.cn
liming |mmm@yahoo.com.cn
liming |aa@sina.com;mmm@yahoo.com.cn
我想统计出来的结果是这样
Mail_To |Num
-------------------------------
mmm@yahoo.com.cn |4
aa@sina.com |3
bb@sina.com |2
baby@hotmail.com |1
也就是统计liming都给哪些人发了邮件,按次数排倒序,最麻烦的是收件人是用";"分割开的,搞了好久没有搞出来,大家谁有什么好办法?谢谢大家100分不够再加!
[解决办法]
------------------------------ Author :SQL77(只为思齐老)-- Date :2010-03-09 15:17:54-- Version:-- Microsoft SQL Server 2000 - 8.00.194 (Intel X86) -- Aug 6 2000 00:57:48 -- Copyright (c) 1988-2000 Microsoft Corporation-- Desktop Engine on Windows NT 5.1 (Build 2600: Service Pack 3)--------------------------------> 测试数据：#TBif object_id('tempdb.dbo.#TB') is not null drop table #TBgo create table #TB([Mail_From] varchar(6),[Mail_To] varchar(40))insert #TBselect 'liming','aa@sina.com;bb@sina.com;mmm@yahoo.com.cn' union allselect 'liming','aa@sina.com' union allselect 'liming','bb@sina.com' union allselect 'liming','baby@hotmail.com;mmm@yahoo.com.cn' union allselect 'liming','mmm@yahoo.com.cn' union allselect 'liming','aa@sina.com;mmm@yahoo.com.cn'--------------开始查询--------------------------SELECT Mail_From, Mail_TO,COUNT(1) C FROM (select Mail_From,SUBSTRING( Mail_To,NUMBER,CHARINDEX(';',Mail_To+';',NUMBER)-NUMBER)Mail_ToFROM #TB,MASTER..SPT_VALUES WHERE TYPE='P' AND SUBSTRING(';'+Mail_To,NUMBER,1)=';')T GROUP BY Mail_From, Mail_TO ORDER BY 3 DESC----------------结果----------------------------（所影响的行数为 6 行）Mail_From Mail_TO C --------- ---------------------------------------- ----------- liming mmm@yahoo.com.cn 4liming aa@sina.com 3liming bb@sina.com 2liming baby@hotmail.com 1（所影响的行数为 4 行）/* */
[解决办法]
--> 测试数据：[tb]if object_id('[tb]') is not null drop table [tb]create table [tb]([Mail_From] varchar(6),[Mail_To] varchar(40))goinsert [tb]select 'liming','aa@sina.com;bb@sina.com;mmm@yahoo.com.cn' union allselect 'liming','aa@sina.com' union allselect 'liming','bb@sina.com' union allselect 'liming','baby@hotmail.com;mmm@yahoo.com.cn' union allselect 'liming','mmm@yahoo.com.cn' union allselect 'liming','aa@sina.com;mmm@yahoo.com.cn'select Mail_To=substring(t.Mail_To,r.number,charindex(';',t.Mail_To+';',r.number)-r.number),count(1) as Numfrom tb t,master..spt_values rwhere r.number<=len(t.Mail_To) and r.type='p' and substring(';'+t.Mail_To,r.number,1)=';'group by substring(t.Mail_To,r.number,charindex(';',t.Mail_To+';',r.number)-r.number)Mail_To Num ---------------------------------------- ----------- aa@sina.com 3baby@hotmail.com 1bb@sina.com 2mmm@yahoo.com.cn 4（所影响的行数为 4 行）
[解决办法]
--参考拆分表:--> --> (Roy)生成測試數據 if not object_id('Tab') is null drop table TabGoCreate table Tab([Col1] int,[COl2] nvarchar(5))Insert Tabselect 1,N'a,b,c' union allselect 2,N'd,e' union allselect 3,N'f'Go--SQL2000用辅助表:if object_id('Tempdb..#Num') is not null drop table #Numgoselect top 100 ID=Identity(int,1,1) into #Num from syscolumns a,syscolumns bSelect a.Col1,COl2=substring(a.Col2,b.ID,charindex(',',a.Col2+',',b.ID)-b.ID) from Tab a,#Num bwhere charindex(',',','+a.Col2,b.ID)=b.ID --也可用 substring(','+a.COl2,b.ID,1)=','--2000不使用辅助表Select a.Col1,COl2=substring(a.Col2,b.number,charindex(',',a.Col2+',',b.number)-b.number) from Tab a join master..spt_values b ON B.type='p' AND B.number BETWEEN 1 AND LEN(A.col2)where substring(','+a.COl2,b.number,1)=','SQL2005用Xml:select a.COl1,b.Col2from (select Col1,COl2=convert(xml,'<root><v>'+replace(COl2,',','</v><v>')+'</v></root>') from Tab)aouter apply (select Col2=C.v.value('.','nvarchar(100)') from a.COl2.nodes('/root/v')C(v))bSQL05用CTE:;with roy as (select Col1,COl2=cast(left(Col2,charindex(',',Col2+',')-1) as nvarchar(100)),Split=cast(stuff(COl2+',',1,charindex(',',Col2+','),'') as nvarchar(100)) from Tabunion allselect Col1,COl2=cast(left(Split,charindex(',',Split)-1) as nvarchar(100)),Split= cast(stuff(Split,1,charindex(',',Split),'') as nvarchar(100)) from Roy where split>'')select COl1,COl2 from roy order by COl1 option (MAXRECURSION 0)生成结果:/*Col1 COl2----------- -----1 a1 b1 c2 d2 e3 f*/
[解决办法]
create table [tb]([Mail_From] varchar(6),[Mail_To] varchar(40))goinsert [tb]select 'liming','aa@sina.com;bb@sina.com;mmm@yahoo.com.cn' union allselect 'liming','aa@sina.com' union allselect 'liming','bb@sina.com' union allselect 'liming','baby@hotmail.com;mmm@yahoo.com.cn' union allselect 'liming','mmm@yahoo.com.cn' union allselect 'liming','aa@sina.com;mmm@yahoo.com.cn'SELECT DISTINCT A.Mail_From,B.MAILFROM (SELECT Mail_From,CONVERT(XML,'<root><row>'+REPLACE(Mail_To,';','</row><row>')+'</row></root>') AS Mail_To FROM tb)aOUTER APPLY (SELECT T.C.value('.','nvarchar(100)') AS MAIL FROM a.Mail_To.nodes('/root/row') T(C))bMail_From MAIL--------- ---------------------------liming aa@sina.comliming baby@hotmail.comliming bb@sina.comliming mmm@yahoo.com.cn(4 行受影响)
[解决办法]
/*标题：数据拆分1作者：爱新觉罗.毓华(十八年风雨,守得冰山雪莲花开)时间：2008-11-20地点：广东深圳描述有表tb, 如下:id value----------- -----------1 aa,bb2 aaa,bbb,ccc欲按id,分拆value列, 分拆后结果如下:id value----------- --------1 aa1 bb2 aaa2 bbb2 ccc*/--1. 旧的解决方法(sql server 2000)SELECT TOP 8000 id = IDENTITY(int, 1, 1) INTO # FROM syscolumns a, syscolumns b SELECT A.id, value = SUBSTRING(A.[value], B.id, CHARINDEX(',', A.[value] + ',', B.id) - B.id)FROM tb A, # BWHERE SUBSTRING(',' + A.[value], B.id, 1) = ','DROP TABLE #--2. 新的解决方法(sql server 2005) create table tb(id int,value varchar(30))insert into tb values(1,'aa,bb')insert into tb values(2,'aaa,bbb,ccc')goSELECT A.id, B.valueFROM( SELECT id, [value] = CONVERT(xml,'<root><v>' + REPLACE([value], ',', '</v><v>') + '</v></root>') FROM tb)AOUTER APPLY( SELECT value = N.v.value('.', 'varchar(100)') FROM A.[value].nodes('/root/v') N(v))BDROP TABLE tb/*id value----------- ------------------------------1 aa1 bb2 aaa2 bbb2 ccc(5 行受影响)*/
[解决办法]
type='p'代表的是表的类型
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那就一个一个字段拆分,然后union all 起来,再统计.
[解决办法]
该说的楼上都。。。都说了
谢谢#2的测试数据 我用函数试一下
--合并表里的Mail_To、Mail_cc、Mail_bcc三列里的邮件地址字符串 @id 为指定用户名 如 limingCREATE FUNCTION dbo.F_MateRow(@id varchar(20))returns varchar(8000)AS BEGIN declare @str varchar(8000) select @str=isnull(@str+';','')+Mail_To from TB where Mail_From=@id select @str=isnull(@str+';','')+Mail_cc from TB where Mail_From=@id select @str=isnull(@str+';','')+Mail_bcc from TB where Mail_From=@id return @strEND--分割字符串CREATE FUNCTION dbo.fun_get_SplitStr(@SourceSql varchar(8000),@StrSeprate varchar(100))returns @temp table(F1 varchar(100))AS BEGIN declare @ch as varchar(100) set @SourceSql =@SourceSql+@StrSeprate while(@SourceSql<>'') BEGIN set @ch=left(@SourceSql,charindex(@StrSeprate,@SourceSql,1)-1) insert @temp values(@ch) set @SourceSql=stuff(@SourceSql,1,charindex(@StrSeprate,@SourceSql,1),'') END return END---查询declare @str varchar(8000)select @str=dbo.F_MateRow('liming')select F1 as MailAdress,count(1) as Tot from dbo.fun_get_SplitStr(@str,';') group by F1/*结果MailAdress Tot ---------------------------aa@sina.com 5baby@hotmail.com 7bb@sina.com 6mmm@yahoo.com.cn 10*/