帮忙看看是什么导致程序中断异常的？
各位帮忙调试下，我实在是找不到错误潜伏在哪～谢谢～
#include <iostream>
#include <vector>
using namespace std;
vector <int> vec;
vector <int> ::iterator iter;
int i,j;
int* q;
int n;
int* putarr(int **p,int lhs,int rhs)
{ //lhs为行数，rhs为列数
if(i == 0)
{
if(j != (rhs-1))
{
q = &p[i][j+1];
*q = *iter;
iter ++;
return q;
}
q = &p[i+1][j];
*q = *iter;
iter ++;
return q;
}
else if(j ==(rhs-1))
{
if(i != (lhs-1))
{
q = &p[i+1][j];
*q = *iter;
iter ++;
return q;
}
q = &p[i][j-1];
*q = *iter;
iter ++;
return q;
}
else if(i ==(lhs-1))
{
if(j != 0)
{
q = &p[j][j-1];
*q = *iter;
iter ++;
return q;
}
q = &p[i-1][j];
*q = *iter;
iter ++;
return q;
}
else if(j == 0)
{
if(i != 0)
{
q = &p[i-1][j];
*q = *iter;
iter ++;
return q;
}
q = &p[i-1][j];
*q = *iter;
iter ++;
return q;
}
else
{
if((p[i-1][j] == 0)&&(p[i][j-1] != 0)&&(p[i+1][j] != 0)&&(p[i][j+1] != 0))
{
q = & p[i-1][j];
*q = *iter;
iter ++;
return q;
}
else if((p[i-1][j] != 0)&&(p[i][j-1] == 0)&&(p[i+1][j] != 0)&&(p[i][j+1] != 0))
{
q = &p[i][j-1];
*q = *iter;
iter ++;
return q;
}
else if((p[i-1][j] != 0)&&(p[i][j-1] != 0)&&(p[i+1][j] == 0)&&(p[i][j+1] != 0))
{
q = &p[i+1][j];
*q = *iter;
iter ++;
return q;
}
else if((p[i-1][j] != 0)&&(p[i][j-1] != 0)&&(p[i+1][j] != 0)&&(p[i][j+1] == 0))
{
q = &p[i][j+1];
*q = *iter;
iter ++;
return q;
}
else if((p[i-1][j] == 0)&&(p[i][j+1] == 0))
{
q = &p[i][j-1];
*q = *iter;
iter ++;
return q;
}
else if((p[i][j+1] == 0)&&(p[i+1][j] == 0))
{
q = &p[i][j+1];
*q = *iter;
iter ++;
return q;
}
else if((p[i+1][j] == 0)&&(p[i][j-1] == 0))
{
q = &p[i+1][j];
*q = *iter;
iter ++;
return q;
}
else if((p[i][j-1] ==0)&&(p[i-1][j] == 0))
{
q = & p[i-1][j];
*q = *iter;
iter ++;
return q;
}
else return q = 0;
}
}
int main()
{
i = 0;
j = 0;
cout < < "输入数组的行数和列数n: " ;
cin > > n;
for(int z = 1; z != n*n + 1; ++z)
vec.push_back(z);
iter = vec.begin();
int** a = new int*[n];
for(int x = 0; x != n; ++x)
a[x] = new int[n];
for(int x = 0; x != n; ++x)
for(int y = 0; y != n; ++y)
a[x][y] = 0;
a[0][0] = 1;
q = &a[0][0];
while(q)
putarr(a,n,n);
for(int x = 0; x != n; ++x)
{
for(int y = 0; y != n; ++y)
cout < < a[x][y] < < " ";
cout < < '\n ';
}
for(int k = n; k != 0; --k)
delete []a[k-1];
delete []a;
return 0;
}
[解决办法]
这么长.......
[解决办法]
while(q)
putarr(a,n,n);
====>
if(q)
putarr(a,n,n);
