Windows Mobile的服务程序
我想在WM 上写一个后台服务程序，截获系统的消息，当每次弹出一个新程序时，都能获知该程序的名称，请高手指点一二，谢谢
[解决办法]
实现你的要求最好的思路是利用 dll inject技术，在.dll文件中利用GetModuleFileName函数得到加载该.dll文件的每个新进程的名称。
[解决办法]
here are times when a DLL must be automatically added to a process space to perform a required action, for example, a debugging tool that tracks some actions.
If neither the source code nor the ability to build the code is available, you are limited in the kinds of debugging you can perform. The kernel can load a DLL into any process space.
To enable this process, add the name of the DLL to the following registry key:
Copy Code
HKEY_LOCAL_MACHINE\SYSTEM\KERNEL
"InjectDLL" = REG_MULTI_SZ : "MyDLL1.DLL","MyDLL2.DLL",
The data type is REG_MULTI_SZ or an array of strings, which can list more than one DLL. The name of the DLL can contain the full path and file name, or just the file name.
Applications that install DLLs to be injected into a process should append or remove only their specific DLL from the registry.
When a process is created and all implicitly-linked DLLs are loaded, the kernel loads each DLL listed in InjectDLL. Failure to load the DLL does not prevent the application from launching. A DLL could fail to load if the DLL returns FALSE in DllMain or if the application is privileged and the DLL being loaded is not. DLLs can check in DLLMain to determine what process they are being loaded into by calling GetModuleFileName. The values you need to pass are (NULL, &Filename, nSize)
