java内存分析
class Point {
private double x;
private double y;
Point(double x1, double y1) {
x = x1;
y = y1;
}
public double getX() { return x; }
public double getY() { return y; }
public void setX(double i) { x = i; }
public void setY(double i) { y = i; }
}
class Circle {
private Point o;
private double radius;
Circle(Point p, double r) {
o = p;
radius = r;
}
Circle(double r) {
o = new Point(0.0, 0.0);
radius = r;
}
boolean contains(Point p) {
double x = p.getX() - o.getX();
double y = p.getY() - o.getY();
if(x*x + y*y > radius * radius) return false;
else return true;
}
public void setO(double x, double y) {
o.setX(x);
o.setY(y);
}
public Point getO() { return o; }
public double getRadius() { return radius;}
public void setRadius(double r) { radius = r;}
public double area() {
return 3.14 * radius * radius;
}
}
public class TestCircle {
public static void main(String args[]) {
Circle c1 = new Circle(new Point(1.0,2.0), 2.0);
Circle c2 = new Circle(5.0);
System.out.println("c1:("+c1.getO().getX()+","
+c1.getO().getY()+"),"+c1.getRadius());
System.out.println("c2:("+c2.getO().getX()
+","+c2.getO().getY()+"),"+c2.getRadius());
System.out.println("c1 area = "+c1.area());
System.out.println("c1 area = "+c2.area());
c1.setO(5,6);
c2.setRadius(9.0);
System.out.println("c1:("+c1.getO().getX()+","
+c1.getO().getY()+"),"+c1.getRadius());
System.out.println("c2:("+c2.getO().getX()+","
+c2.getO().getY()+"),"+c2.getRadius());
System.out.println("c1 area = "+c1.area());
System.out.println("c1 area = "+c2.area());
Point p1 = new Point(5.2, 6.3);
System.out.println(c1.contains(p1));
System.out.println(c1.contains(new Point(10.0,9.0)));
}
}
[解决办法]
[解决办法]
这个好像尚学堂的视频里有讲啊 有内存分析的啊
[解决办法]
看来都是看尚学堂长大的，我告诉你，简单内存分析会了就行了，
别再心里留下阴影就行了。既然这个问题你遇到了就搞定他，以后别再
分析了，关键是能理解面向对象就行了，OK？
