有关PHP分页显示的问题
我在听PHP100视频中有关介绍分页原理的介绍。根据提供的代码，进行运行后发现换页无法进行，url还一直显示？page=2page=3page=4等，刚开始找到原因是因为ereg_replace函数已经在5.3的版本中不用，改为preg_replace还是不行，请麻烦高手给予解答。谢谢。
代码：
<?php
function _PAGEFT($totle, $displaypg = 20, $url = '') {
global $page, $firstcount, $pagenav, $_SERVER;
$GLOBALS["displaypg"] = $displaypg;
if (!$page)
$page = 1;
if (!$url) {
$url = $_SERVER["REQUEST_URI"];
}
//URL分析:
$parse_url = parse_url($url);
$url_query = $parse_url["query"]; //单独取出URL的查询字串
if ($url_query) {
$url_query = preg_replace("/(^|&)page=$page/","", $url_query);
$url = str_replace($parse_url["query"], $url_query, $url);
if ($url_query)
$url .= "&page";
else
$url .= "page";
} else {
$url .= "?page";
}
$lastpg = ceil($totle / $displaypg); //最后页,也是总页数
$page = min($lastpg, $page);
$prepg = $page -1; //上一页
$nextpg = ($page == $lastpg ? 0 : $page +1); //下一页
$firstcount = ($page -1) * $displaypg;
//开始分页导航条代码:
$pagenav = "显示第 <B>" . ($totle ? ($firstcount +1) : 0) . "</B>-<B>" . min($firstcount + $displaypg, $totle) . "</B> 条记录,共 $totle 条记录";
//如果只有一页则跳出函数:
if ($lastpg <= 1)
return false;
$pagenav .= " <a href='$url=1'>首页</a> ";
if ($prepg)
$pagenav .= " <a href='$url=$prepg'>前页</a> ";
else
$pagenav .= " 前页 ";
if ($nextpg)
$pagenav .= " <a href='$url=$nextpg'>后页</a> ";
else
$pagenav .= " 后页 ";
$pagenav .= " <a href='$url=$lastpg'>尾页</a> ";
//下拉跳转列表,循环列出所有页码:
$pagenav .= " 到第 <select name='topage' size='1' onchange='window.location="$url="+this.value'>\n";
for ($i = 1; $i <= $lastpg; $i++) {
if ($i == $page)
$pagenav .= "<option value='$i' selected>$i</option>\n";
else
$pagenav .= "<option value='$i'>$i</option>\n";
}
$pagenav .= "</select> 页,共 $lastpg 页";
}
include("conn.php");
$result=mysql_query("SELECT * FROM `p_newsbase`");
$total=mysql_num_rows($result);
//调用pageft(),每页显示10条信息(使用默认的20时,可以省略此参数),使用本页URL(默认,所以省略掉).
_PAGEFT($total,1);
echo $pagenav;
$result=mysql_query("SELECT * FROM `p_newsbase` limit $firstcount,$displaypg ");
while($row=mysql_fetch_array($result)){
echo "<hr><b>".$row['author']." | ".$row['title'];
}
?
[解决办法]
1、函数 _PAGEFT 最后一行要加入 return $pagenav;
2、调用时要这样写
$page = isset($_GET['page']) ? $_GET['page'] : 1;
echo _PAGEFT(100);//你打算处理的总记录数
