Python 获取当前目录下所有文件夹的大小
Python 获取当前目录下所有文件夹的大小。方便一目了然的去删除大文件目录
python 2.7下实现
#!/usr/bin/python#-*- coding:gbk -*-import urllib2import urllibimport osimport shutilhomedir = os.getcwd()from os.path import join, getsize'''获取当前文件夹，和文件夹大小放在要统计的文件夹下'''FOLDER_LIST=[]def getdirsize(dir): size = 0L for root, dirs, files in os.walk(dir): size += sum([getsize(join(root, name)) for name in files]) return sizedef getFileSize(size): if size/1024>1: if size/(1024*1024)>1: return '%0.2fMB' %float(size/(1024*1024)) else: return '%0.2fKB' %float(size/1024) else: return '%0.2fKB' %float(size/1024)def sort(A,num): for i in range(len(A)): (A[i][0],A[i][num])=(A[i][num],A[i][0]) A.sort(reverse=True) for i in range(len(A)): (A[i][0],A[i][num])=(A[i][num],A[i][0])for i in os.listdir('.'): if os.path.isdir(i): fileSize = getdirsize(unicode(homedir+'\\'+i,'gbk')) FOLDER_LIST.append([homedir+'\\'+i,fileSize]) print homedir+'\\'+i+'\t文件大小:%s' %(getFileSize(float(fileSize)))sort(FOLDER_LIST,1)print '*********************排序后*********************'for arr in FOLDER_LIST: print arr[0]+'\t文件大小:%s' %(getFileSize(float(arr[1]))) print '---------------------------------------------------------'os.system('pause')