时间间隔计算
start_time end_time
2013-09-11 17:26:02.382 2013-09-24 10:38:01.41
2013-09-18 17:02:40.444 2013-09-22 15:27:58.984
2013-09-18 08:21:32.036 2013-09-22 15:31:52.499
2013-09-13 16:28:29.832 2013-09-16 09:41:47.988
2013-09-09 10:59:59.835 2013-09-10 14:06:21.223
要求计算这两个列的时间差 但是要去除9月份的正常休假并且只计算正常工作时间（上午8:30--12:00 下午14:00--18:00）
计算结果如下：
start_time end_time diff_time（小时）
2013-09-11 17:26:02.382 2013-09-24 10:38:01.41 55.1
2013-09-18 17:02:40.444 2013-09-22 15:27:58.984 5.9
2013-09-18 08:21:32.036 2013-09-22 15:31:52.499 12.5
2013-09-13 16:28:29.832 2013-09-16 09:41:47.988 2.7
2013-09-09 10:59:59.835 2013-09-10 14:06:21.223 1.1
请各位大大帮忙看看这个时间差应该怎么计算 谢谢了 时间差
[解决办法]
use test
if object_id('tab') is not null
drop table tab
if object_id('holiday') is not null
drop table holiday
go
create table tab(start_time datetime,end_time datetime)
insert into tab
select '2013-09-11 17:26:02.382','2013-09-24 10:38:01.41' union
select '2013-09-18 17:02:40.444','2013-09-22 15:27:58.984' union
select '2013-09-18 08:21:32.036','2013-09-22 15:31:52.499' union
select '2013-09-13 16:28:29.832','2013-09-16 09:41:47.988' union
select '2013-09-09 10:59:59.835','2013-09-09 14:06:21.223'
create table holiday(h_date datetime)
insert into holiday
select '2013-09-01' union
select '2013-09-07' union
select '2013-09-08' union
select '2013-09-14'union
select '2013-09-15'union
select '2013-09-19'union
select '2013-09-20'union
select '2013-09-21'union
select '2013-09-29'
--;with sel as(select start_time oldstart,end_time oldend,case when exists(select 1 from holiday where
--h_date=convert(varchar(10),t.start_time,114)) then convert(varchar(10),t.start_time,121)+' 19:00' end as start_time,
--case when exists(select 1 from holiday where h_date=convert(varchar(10),t.end_time,114)) then
-- convert(varchar(10),t.end_time,121)+' 19:00' end as end_time
--from tab t)
select start_time,end_time ,diff_time=
case when datediff(d,start_time,end_time)=0
then (
case when convert(varchar(10),start_time,114)<='08:30' then 7.5
when convert(varchar(10),start_time,114) between '08:31' and '12:00' then 4+datediff(n,start_time,
convert(varchar(10),start_time,121)+' 12:00')/60.0
when convert(varchar(10),start_time,114) between '12:01' and '14:00' then 4
when convert(varchar(10),start_time,114) between '14:01' and '18:00' then
datediff(n,start_time,convert(varchar(10),start_time,121)+' 18:00')/60.0
else 0 end)-
(case when convert(varchar(10),end_time,114)<='08:30' then 7.5
when convert(varchar(10),end_time,114) between '08:31' and '12:00' then 4+datediff(n,end_time,
convert(varchar(10),end_time,121)+' 12:00')/60.0
when convert(varchar(10),end_time,114) between '12:01' and '14:00' then 4
when convert(varchar(10),end_time,114) between '14:01' and '18:00' then
datediff(n,end_time,convert(varchar(10),end_time,121)+' 18:00')/60.0
else 0 end)
when datediff(d,start_time,end_time)>0
then (case when convert(varchar(10),start_time,114)<='08:30' then 7.5
when convert(varchar(10),start_time,114) between '08:31' and '12:00' then 4+datediff(n,start_time,
convert(varchar(10),start_time,121)+' 12:00')/60.0
when convert(varchar(10),start_time,114) between '12:01' and '14:00' then 4
when convert(varchar(10),start_time,114) between '14:01' and '18:00' then
datediff(n,start_time,convert(varchar(10),start_time,121)+' 18:00')/60.0
else 0 end)+
(case when convert(varchar(10),end_time,114)<='08:30' then 7.5
when convert(varchar(10),end_time,114) between '8:31' and '12:00' then 4+datediff(n,end_time,
convert(varchar(10),end_time,121)+' 12:00')/60.0
when convert(varchar(10),end_time,114) between '12:01' and '14:00' then 4
when convert(varchar(10),end_time,114) between '14:01' and '18:00' then
datediff(n,end_time,convert(varchar(10),end_time,121)+' 18:00')/60.0
else 0 end)+(
datediff(d,start_time,end_time)-1-(select count(1) from holiday where
h_date between tab.start_time and tab.end_time))*7.5
end
from tab
if object_id('tab') is not null
drop table tab
if object_id('holiday') is not null
drop table holiday
go
create table tab(start_time datetime,end_time datetime)
insert into tab
select '2013-09-11 17:26:02.382','2013-09-24 10:38:01.41' union
select '2013-09-18 17:02:40.444','2013-09-22 15:27:58.984' union
select '2013-09-18 08:21:32.036','2013-09-22 15:31:52.499' union
select '2013-09-13 16:28:29.832','2013-09-16 09:41:47.988' union
select '2013-09-09 10:59:59.835','2013-09-09 14:06:21.223'
create table holiday(h_date datetime)
insert into holiday
select '2013-09-01' union
select '2013-09-07' union
select '2013-09-08' union
select '2013-09-14'union
select '2013-09-15'union
select '2013-09-19'union
select '2013-09-20'union
select '2013-09-21'union
select '2013-09-29'
WITH calendar --产生日历
AS
(
SELECT CAST('2013-09-01' as varchar(10)) AS r --月份的开始日期
UNION ALL
SELECT convert(VARCHAR(10),dateadd(day,1,r),120)
FROM calendar
WHERE r < '2013-09-30' --月份的结束日期
),
tt --计算时间间隔，单位为秒
as
(
SELECT t.start_time,
t.end_time,
c.r,
h.h_date,
/*
通过tab表和calendar表的关联，就能把开始时间到结束时间，多对应的多天，
都给关联出来，
比如开始时间 2013-09-18 08:21:32.037结束时间 2013-09-22 15:31:52.500，
其实就是，18、19、20、21、22这一共5天，会由原来的1条记录，现在变为5条记录。
如果h_date为null，说明这一天不是假日,
就需要计算时间间隔，有几种可能性：
1.开始时间和结束时间，在同一天的
2.当前日期和开始日期相同
3.当前日期和结束日期相同
4.当前日期是在开始日期和结束日期之间的某天
如果h_date是null，那么返回0，说明是节假日，就不用计算时间间隔了
*/
case when h_date IS null and
convert(varchar(10),t.start_time_temp,120) = c.r and
CONVERT(varchar(10),t.end_time_temp,120) = c.r
then case when convert(varchar(5),t.start_time_temp,114) between '08:30' and '12:00'
and not (convert(varchar(5),t.end_time_temp,114) between '08:30' and '12:00')
then DATEDIFF(second,t.start_time_temp,c.r +' 12:00:00')
else 0
end +
case when convert(varchar(5),t.end_time_temp,114) between '14:00' and '18:00'
and not (convert(varchar(5),t.start_time_temp,114) between '14:00' and '18:00')
then DATEDIFF(second,c.r+' 14:00:00',t.end_time_temp)
else 0
end +
case when (convert(varchar(5),t.start_time_temp,114) between '08:30' and '12:00'
and convert(varchar(5),t.end_time_temp,114) between '08:30' and '12:00')
or
(convert(varchar(5),t.end_time_temp,114) between '14:00' and '18:00'
and convert(varchar(5),t.start_time_temp,114) between '14:00' and '18:00')
then DATEDIFF(SECOND,t.start_time_temp,t.end_time_temp)
else 0
end
/*
注意下面的计算逻辑是，如果这天不是假日，同时与开始日期相同
那么就要计算时间间隔，如果时间是在上午的工作时间范围内，
那么用当前日期的12点，减去开始日期，就是时间间隔，但还必须要加上下午的工作时间，
也就是4个小时，转化为秒数，就是4*3600
*/
when h_date IS null and
convert(varchar(10),t.start_time_temp,120) = c.r
then case when convert(varchar(5),t.start_time_temp,114) between '08:30' and '12:00'
then DATEDIFF(second,t.start_time_temp,c.r +' 12:00:00') + 4 * 3600
else 0
end +
case when convert(varchar(5),t.start_time_temp,114) between '14:00' and '18:00'
then DATEDIFF(second,t.start_time_temp,c.r +' 18:00:00')
else 0
end
when h_date IS null and
CONVERT(varchar(10),t.end_time_temp,120) = c.r
then case when convert(varchar(5),t.end_time_temp,114) between '08:30' and '12:00'
then DATEDIFF(second,c.r +' 08:30:00',t.end_time_temp)
else 0
end +
case when convert(varchar(5),t.end_time_temp,114) between '14:00' and '18:00'
then DATEDIFF(second,c.r +' 14:00:00',t.end_time_temp) + 3.5 * 3600
else 0
end
when h_date is null and
convert(varchar(10),t.start_time_temp,120) < c.r and
CONVERT(varchar(10),t.end_time_temp,120) > c.r
then 7.5 * 3600
when h_date IS null
then 0
end as seconds
FROM
(
/*
这里之所以要转换，是由于有些时间比如 start_time为2013-09-18 08:21:32.037,
不在正常工作时间（上午8:30--12:00 下午14:00--18:00）内，
所以要先转化为正常工作时间，否则后面的case when的逻辑判断就太复杂了。
*/
SELECT start_time,
end_time,
case when CONVERT(varchar(5),start_time,114) < '08:30'
then cast(CONVERT(varchar(10),start_time,120) + ' 08:30:00' AS datetime)
when CONVERT(varchar(5),start_time,114) between '12:00' and '14:00'
then cast(CONVERT(varchar(10),start_time,120) + ' 12:00:00' AS datetime)
else start_time
end as start_time_temp,
case when CONVERT(varchar(5),end_time,114) between '12:00' and '14:00'
then cast(CONVERT(varchar(10),end_time,120) + ' 12:00:00' AS datetime)
when CONVERT(varchar(5),end_time,114) > '18:00'
then cast(CONVERT(varchar(10),end_time,120) + ' 18:00:00' AS datetime)
else end_time
end as end_time_temp
FROM tab
) t
inner join calendar c
on convert(varchar(10),t.start_time,120) <= c.r
and convert(varchar(10),t.end_time,120) >= c.r
left join holiday h
on c.r = h.h_date
--OPTION(MAXRECURSION 1000) --限制最大递归次数
)
--select * from tt
select start_time,
end_time,
--汇总秒数，同时转化为小时
cast(round(SUM(seconds) / 3600 ,1,1) as numeric(10,1)) as diff_time
from tt
group by start_time,
end_time
/*
start_timeend_timediff_time
2013-09-09 10:59:59.8372013-09-09 14:06:21.2231.1
2013-09-13 16:28:29.8332013-09-16 09:41:47.9872.7
2013-09-18 17:02:40.4432013-09-22 15:27:58.9835.9
2013-09-18 08:21:32.0372013-09-22 15:31:52.50012.5
2013-09-11 17:26:02.3832013-09-24 10:38:01.41055.1
*/
