SSH整合例子（仅用到ss处理登录demo）出现异常
帖代码先
---------------------------------
public class User { // 实体类
private String name;
private String password;
//省略set get方法
｝
----------------------------------
public interface IUserService {// 接口
boolean login(User user);
boolean register(User user);
}
------------------------------------//接口实现类
public class UserService implements IUserService {
public boolean login(User user){
if("user".equals(user.getName())&&"user".equals(user.getPassword()))
{
return true;
}else{
return false;
}
}
public boolean register(User user){
if("qqq".equals(user.getName())&&"qqq".equals(user.getPassword())){
return true;
}else{
return false;}
}
}
------------------------
//action
package com.action;
import com.opensymphony.xwork2.ActionSupport;
import com.service.IUserService;
import com.vo.User;
public class UserAction extends ActionSupport {
/**
*
*/
private static final long serialVersionUID = 1L;
private User user = new User();
private IUserService service;
public User getUser() {
return user;
}
public void setUser(User user) {
this.user = user;
}
public IUserService getService() {
return service;
}
public void setService(IUserService service) {
this.service = service;
}
public String login(){
System.out.println(getService());
System.out.println(user.getName());
if(service.login(user)){
return SUCCESS;
}else{
return ERROR;
}
}
public String register(){
System.out.println(user.getName());
if(service.register(user)){
return SUCCESS;
}else{
return ERROR;
}
}
}
-----------------------------------------------------下面的所有配置文件
web.xml
<?xml version="1.0" encoding="UTF-8"?>
<web-app version="2.5"
xmlns=" http://java.sun.com/xml/ns/javaee"
xmlns:xsi=" http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation=" http://java.sun.com/xml/ns/javaee
http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd">
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>classpath*:applicationContext.xml</param-value>
</context-param>
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<welcome-file-list>
<welcome-file>index.jsp</welcome-file>
</welcome-file-list>
<filter>
<filter-name>struts2</filter-name>
<filter-class>
org.apache.struts2.dispatcher.ng.filter.StrutsPrepareAndExecuteFilter
</filter-class>
</filter>
<filter-mapping>
<filter-name>struts2</filter-name>
<url-pattern>/*</url-pattern>
</filter-mapping></web-app>
-------------------------
struts.xml
<?xml version="1.0" encoding="UTF-8" ?>
<!DOCTYPE struts PUBLIC "-//Apache Software Foundation//DTD Struts Configuration 2.1//EN" " http://struts.apache.org/dtds/struts-2.1.dtd">
<struts>
<constant name="struts.objectFactory" value="spring" />
<package name="default" extends="struts-default" namespace="/">
<action name="user" class="com.action.UserAction">
<result name="success">/success.jsp</result>
<result name="error">/failed.jsp</result>
</action>
</package>
</struts>
--------------------------------------
spring 配置文件applicationContext.xml
<?xml version="1.0" encoding="UTF-8"?>
<beans
xmlns=" http://www.springframework.org/schema/beans"
xmlns:xsi=" http://www.w3.org/2001/XMLSchema-instance"
xmlns:p=" http://www.springframework.org/schema/p"
xsi:schemaLocation=" http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-2.5.xsd">
<bean id="UserserviceImpl" class="com.service.UserService"/>
<bean id="userAction" class="com.action.UserAction" autowire="byType">
<property name="service" ref="UserserviceImpl"/>
</bean>
</beans>
--------------------------------jsp
<%@ page language="java" import="java.util.*" pageEncoding="ISO-8859-1"%>
<%
String path = request.getContextPath();
String basePath = request.getScheme()+"://"+request.getServerName()+":"+request.getServerPort()+path+"/";
%>
<%@ taglib uri="/struts-tags" prefix="s" %>
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN">
<html>
<head>
<base href="<%=basePath%>">
<title>My JSP 'index.jsp' starting page</title>
<meta http-equiv="pragma" content="no-cache">
<meta http-equiv="cache-control" content="no-cache">
<meta http-equiv="expires" content="0">
<meta http-equiv="keywords" content="keyword1,keyword2,keyword3">
<meta http-equiv="description" content="This is my page">
<!--
<link rel="stylesheet" type="text/css" href="styles.css">
-->
</head>
<body>
This is my JSP page. <br>-------------------------------
<br>-----------------------login form---------------------------------
<s:form action="user!login.action" >
input your user account:<s:textfield name="user.name"></s:textfield>
input your user password:<s:password name="user.password"></s:password>
<s:submit value="login in right now" />
</s:form>
<br>-----------------------register form---------------------------------
<s:form action="user!login.register" >
input your user account:<s:textfield name="user.name"></s:textfield>
input your user password:<s:password name="user.password"></s:password>
<s:submit name=" " value="login in right now" />
</s:form>
</body>
</html>
-------------------------------------------登录异常
type Exception report
message
description The server encountered an internal error () that prevented it from fulfilling this request.
exception
java.lang.NullPointerException
com.action.UserAction.login(UserAction.java:36)
sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:39)
sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:25)
java.lang.reflect.Method.invoke(Method.java:597)
com.opensymphony.xwork2.DefaultActionInvocation.invokeAction(DefaultActionInvocation.java:441)
com.opensymphony.xwork2.DefaultActionInvocation.invokeActionOnly(DefaultActionInvocation.java:280)
com.opensymphony.xwork2.DefaultActionInvocation.invoke(DefaultActionInvocation.java:243)
com.opensymphony.xwork2.interceptor.DefaultWorkflowInterceptor.doIntercept(DefaultWorkflowInterceptor.java:165)
……………………………………………………
……………………………………………………
-------------------------------------------
就是Action中的service获取不到 怎么弄都是空的？？？？ 表单中可以获取到输入的值
在线等！ 谢谢
[解决办法]
将struts.xml中action里的class改为ApplicationContext.xml中bean 的id
<action name="user" class="userAction">
另外，这里要加上<bean id="userAction" class="com.action.UserAction" autowire="byType"scope="prototype">
[解决办法]
同意三L,ApplicationContext.xml里的bean id 应与struts.xml里action的class对应!!
我的异常网推荐解决方案：The server encountered an internal error () that prevented it from fulfilling this request.,http://www.myexception.cn/java-web/317.html
