统计上下班时间的数据库筛选问题
各位大大我语言表达能力比较差希望大家不要介意- -
情况如下：
表的三列为 [id] [time] [device]分别表示工号，打卡时间，打卡设备号（1为上班，2为下班），其中打卡设备号用于区分上班和下班的打卡时间，目前我得到了持续一个月的所有员工的全部打卡记录，都记录在这个表中，现在我想通过sql的筛选计算功能得到类似下面列的新表：
[id] [InTime] [OutTime] [LT]分别表示工号，上班时间，下班时间，在岗时间（也就是下班减去上班），但由于情况特殊，员工的上下班并没有确切的时间段，24小时内都有人上下班，不知道有没有解决方案呢？
[解决办法]
select a.id,a.time as Intime, b.Time as OutTime,
datediff(ss/*以秒记*/,a.time,b.time) as LT
from tb a cross apply
(select top (1)* from tb b where a.ID = b.ID and b.time > a.time
and b.device = 2 order by b.time desc)p
where a.device = 1
WITH test (id,TIME,device)
AS
(
SELECT 1,'2012-09-23 12:10:01',1
UNION ALL
SELECT 1,'2012-09-24 12:10:01',2 --模拟跨天
UNION ALL
SELECT 2,'2012-09-23 12:10:01',1
UNION ALL
SELECT 2,'2012-09-23 14:10:01',2 --模拟当天
)
--SELECT * FROM test
SELECT id,InTime=MAX(CASE WHEN device=1 THEN TIME END ),OutTime=MAX(CASE WHEN device=2 THEN TIME END ),
CASE WHEN DATEPART(DAY,MAX(CASE WHEN device=1 THEN TIME END ))=DATEPART(DAY,MAX(CASE WHEN device=2 THEN TIME END ))
THEN CONVERT(VARCHAR(10),DATEDIFF (hh,MAX(CASE WHEN device=1 THEN TIME END ),MAX(CASE WHEN device=2 THEN TIME END)))+'小时'
+ CONVERT(VARCHAR(10),DATEDIFF (mi,DATEPART(mi,MAX(CASE WHEN device=1 THEN TIME END )),DATEPART(mi,MAX(CASE WHEN device=2 THEN TIME END))))
+'分'+CONVERT(VARCHAR(10),DATEDIFF (ss,DATEPART(ss,MAX(CASE WHEN device=1 THEN TIME END )),DATEPART(ss,MAX(CASE WHEN device=2 THEN TIME END))))+'秒'
ELSE CONVERT(VARCHAR(10),DATEDIFF (hh,MAX(CASE WHEN device=1 THEN TIME END ),MAX(CASE WHEN device=2 THEN TIME END)))+'小时'
+ CONVERT(VARCHAR(10),DATEDIFF (mi,DATEPART(mi,MAX(CASE WHEN device=1 THEN TIME END )),DATEPART(mi,MAX(CASE WHEN device=2 THEN TIME END))))
+'分'+CONVERT(VARCHAR(10),DATEDIFF (ss,DATEPART(ss,MAX(CASE WHEN device=1 THEN TIME END )),DATEPART(ss,MAX(CASE WHEN device=2 THEN TIME END))))+'秒'
END
FROM test
GROUP BY id
/*
----------- ------------------- ------------------- --------------------------------------
1 2012-09-23 12:10:01 2012-09-24 12:10:01 24小时0分0秒
2 2012-09-23 12:10:01 2012-09-23 14:10:01 2小时0分0秒
警告: 聚合或其他 SET 操作消除了 Null 值。
(2 行受影响)
*/
select #a.id ,b.Intime,b.OutTime,
datediff(s,b.OutTime,b.Intime) as LT
from #a cross join(
select case when device=1 then max(time) end as Intime,
case when device=2 then min(time) end as OutTime from #a group by device) as b
