discuz 加密解密 authcode 用Ruby 1.9 实现 （可用）
def self.authcode(str,decode=true,key='',expiry=0) return nil unless str str = decode ? str+'====' : str.gsub(/\\t/,"\t") require 'base64' ckey_length = 4 key = Digest::MD5.hexdigest(!key.empty? ? key : 'asdf') keya = Digest::MD5.hexdigest(key[0,16]) keyb = Digest::MD5.hexdigest(key[16,16]) keyc = decode ? str[0,ckey_length] : Digest::MD5.hexdigest("#{Time.now.to_f} #{Time.now.to_i}")[-ckey_length,ckey_length] cryptkey = keya + Digest::MD5.hexdigest(keya+keyc) key_length = cryptkey.size str = decode ? Base64.decode64(str[ckey_length..-1]) : format("%010d",(expiry!=0 ? expiry + Time.now.to_i : 0)).to_s + Digest::MD5.hexdigest(str+keyb)[0,16]+str str_length = str.size result = '' box = {} (0..255).each { |i| box[i] = i} rndkey = {} (0..255).each do |i| rndkey[i] = (cryptkey[i % key_length,1]).ord #cryptkey[0,i % key_length][0] 这里把[0]改为ord end j = 0 (0..255).each do |i| j = (j + box[i].to_i + rndkey[i].to_i) % 256 tmp = box[i] box[i] = box[j] box[j] = tmp end a=j=0 (0..str_length-1).each do |i| a = (a+1) % 256 j = (j + box[a]) % 256 tmp = box[a] box[a] = box[j] box[j] = tmp ks = box[(box[a].to_i + box[j].to_i)%256] result << (str[i].ord ^ ks.to_i ).chr #( (str[i].to_i ^ ks ).to_s[0] % 256 ).chr 这里把to_i改为ord end if decode if (result[0,10].to_i ==0 || (result[0,10].to_i - Time.now.to_i) > 0) && result[10,16] == (Digest::MD5.hexdigest(result[26..-1] + keyb)[0,16]) return result[26..-1] else return '' end else return keyc+Base64.encode64(result).sub('=','') end end 1 楼 andy.xl 2011-04-21 昨天从新测试了下，不用使用ord函数，这个函数还是可以正常使用的。