串口访问的委托有关问题

2012-12-16

串口访问的委托问题？第一步定义了一个串口基类/// summary/// 串口基类/// /summarypublic abstract

串口访问的委托问题？
第一步定义了一个串口基类
/// <summary>
    /// 串口基类
    /// </summary>
    public abstract class HardwareBase
    {
        public delegate void DataReceivedHander(object sender, SerialDataReceivedEventArgs e);

        public event DataReceivedHander DataReceived;

        /// <summary>
        /// 发送命令
        /// </summary>
        /// <param name="text"></param>
        public abstract void Write(string text);

        /// <summary>
        /// 读串口数据
        /// </summary>
        /// <returns></returns>
        public abstract byte[] Read();

        /// <summary>
        /// 打开串口
        /// </summary>
        public abstract void Open();
    }

第二  写了个串口类
public class SerialPortEx:HardwareBase
    {
        SerialPort serial = null;

        /// <summary>
        /// 构造初始化串口
        /// </summary>
        /// <param name="portName"></param>
        /// <param name="baudRate"></param>
        /// <param name="parity"></param>
        /// <param name="dataBits"></param>
        /// <param name="stopBits"></param>
        public SerialPortEx(string portName, int baudRate, Parity parity, int dataBits, StopBits stopBits)
        {
            serial = new SerialPort(portName, baudRate, parity, dataBits, stopBits);
        }

        /// <summary>
        /// 写串口数据
        /// </summary>
        /// <param name="text"></param>
        public override void Write(string text)
        {
            try
            {
                serial.Write(text);

            }
            catch (Exception ex)
            {
                throw ex;
            }
        }

        /// <summary>
        /// 读取串口数据
        /// </summary>
        /// <returns></returns>
        public override byte[] Read()
        {
            byte[] receivedBuffer = new byte[serial.BytesToRead];
            serial.Read(receivedBuffer, 0, receivedBuffer.Length);
            return receivedBuffer;
        }

        /// <summary>
        /// 打开串口
        /// </summary>
        public override void Open()
        {
            try
            {
                serial.Open();

                serial.DataReceived += new SerialDataReceivedEventHandler(serial_DataReceived);
            }
            catch (Exception ex)
            {
                throw ex;
            }
        }

        /// <summary>
        /// 串口返回数据
        /// </summary>
        /// <param name="sender"></param>
        /// <param name="e"></param>
        public override void serial_DataReceived(object sender, SerialDataReceivedEventArgs e)
        {
            //base.DataReceived(sender, e);
        }

第三步：

       serial = new SerialPortEx(portName, baudRate, parity, dataBits, stopBits);
       serial.Open();
       serial.DataReceived += new HardwareBase.DataReceivedHander(serial_DataReceived);

？？？这里如何通过一个委托事件通知HardwareBase.DataReceivedHander 接收数据？

哪位给指点一下。万分感激
[解决办法]
serial.DataReceived += new HardwareBase.DataReceivedHander(serial_DataReceived);
这一句你已经给 serial.DataReceived 这个委托绑定了方法那么你就调用serial.DataReceived（数据）；
[解决办法]
我是想在第二步的SerialPortEx类里面接收到了串口的数据后主动通知他的上级去做收数据的处理

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