&#x转换为汉字
路遇&#x,研究一下发现就是Unicode不同之处在于%u换成了&#x,还有就是后面多了个分号。
给出转换方法,自己留着备用:
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public static StringBuffer decodeUnicode(String dataStr) {dataStr=dataStr.replace("&#x", "\\u");final StringBuffer buffer = new StringBuffer();String tempStr = "";String operStr = dataStr;if (operStr != null && operStr.indexOf("\\u") == -1)return buffer.append(operStr);if (operStr != null && !operStr.equals("")&& !operStr.startsWith("\\u")) {tempStr = operStr.substring(0, operStr.indexOf("\\u"));operStr = operStr.substring(operStr.indexOf("\\u"), operStr.length());}buffer.append(tempStr);while (operStr != null && !operStr.equals("")&& operStr.startsWith("\\u")) {tempStr = operStr.substring(0, 6);operStr = operStr.substring(7, operStr.length());String charStr = "";charStr = tempStr.substring(2, tempStr.length());char letter = (char) Integer.parseInt(charStr, 16);buffer.append(new Character(letter).toString());if (operStr.indexOf("\\u") == -1) {buffer.append(operStr);} else { tempStr = operStr.substring(0, operStr.indexOf("\\u"));operStr = operStr.substring(operStr.indexOf("\\u"), operStr.length());buffer.append(tempStr);}}return buffer;}?