sql话语 查出某字段的最后一条记录

sql语句 查出某字段的最后一条记录
在一张表上有多个重复的数据，怎么做才能找出不同数据的最后一条记录。
ID stu_id endDate
1 10 2011/10/10
2 10 2011/10/11
3 11 2011/10/12
4 11 2011/10/13
5 12 2011/10/14
6 12 2011/10/15
就是找出
stu_id=10的最后时间
stu_id=11的最后时间
......

[解决办法]
select * from tb a 
 where not exists(select 1 from tb where stu_id=a.stu_id and endDate>a.endDate)
[解决办法]
select * from tb where enddate in(select max(enddate) from tb group by (stu_id))
[解决办法]

SQL code

--sql 2005以上版本select * from (select *,rn=row_number()over(partition by stu_id order by enddate)from tb)awhere rn=2--sql 2000--1、select * from tb a   where not exists(select 1 from tb where stu_id=a.stu_id and endDate>a.endDate)--2、select * from tb where enddate in(select max(enddate) from tb group by (stu_id))
[解决办法]
select * into 新表（可以随意命名，自动根据旧表生成新表表结构） from 旧表 where  id  in (select id from 旧表 where enddate in(select max(enddate) from tb group by (stu_id)) )
[解决办法]
SELECT stu_id MAX(enDate) FROM tableName GROUP BY stu_id

[解决办法]
SELECT stu_id ,MAX(enDate) AS enDate FROM tableName GROUP BY stu_id 
   
 上句忘加逗号。
[解决办法]
SQL code
WITH test (ID, stu_id ,endDate) AS ( SELECT 1, 10, '2011/10/10' UNION ALL  select 2, 10, '2011/10/11' UNION ALL  select 3, 11, '2011/10/12' UNION ALL  select 4 ,11, '2011/10/13' UNION ALL  select 5 ,12, '2011/10/14' UNION ALL  select 6 ,12, '2011/10/15') SELECT * FROM test a  WHERE EXISTS(SELECT 1 FROM ( SELECT stu_id,MAX(enddate)enddate FROM test GROUP BY stu_id) b WHERE  a.stu_id=b.stu_id AND a.enddate=b.enddate)  /* ID          stu_id      endDate ----------- ----------- ---------- 2           10          2011/10/11 4           11          2011/10/13 6           12          2011/10/15  (3 行受影响) */