数据结构与算法：用java数组实现BigInt超大整数设计
中兴的一道笔试题：如果系统要使用超大整数（超过long长度范围），请你设计一个数据结构来存储这种超大型数字以及设计一种算法来实现超大整数加法运算）。
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package com.test;import org.apache.commons.lang.StringUtils;/** * @author jsczxy2 * */public class BigInt {public static void main(String[] args) {BigInt a = new BigInt("367892732043217489143432876442367892732043217489143432876442367892732043217489143432876442367892732043217489143432876442");BigInt b = new BigInt("3678927329999999999999994328736789273299999999999999943287367892732043217489143432876442367892732043217489143432876442");System.out.println(a.toString());System.out.println(b.toString());System.out.println(a.add(b));}private int[] arrayint = new int[100];public BigInt(String num) {//分解数字到int数组中splitNumToArray(num);}public void splitNumToArray(String num) {int j = 0;StringBuffer sb = new StringBuffer();//数字全部翻转后分组截取后再翻转回来加入int数组,这里控制数组中每一个int元素恒定为8位不超过int最大长度num = new StringBuffer(num).reverse().toString();for (int i = 0; i <num.length(); i++) {if (i % 8 == 0) {if (sb != null && !sb.toString().equals("")){arrayint[j] = Integer.valueOf(sb.reverse().toString());j++;sb = new StringBuffer();}}sb.append(num.charAt(i));}if (sb != null) {arrayint[j] = Integer.valueOf(sb.reverse().toString());}}//数组从后开始打印数字,不满8位补齐8位数字用0进行左填充public String printArray(int[] array) {StringBuffer sb = new StringBuffer();boolean isNotFirstInt = false;for (int i = array.length-1; i >=0 ; i--) {if (array[i] != 0) {System.out.println(i+":"+array[i]);if(isNotFirstInt && String.valueOf(array[i]).length()<8){sb.append(StringUtils.leftPad(String.valueOf(array[i]), 8,"0"));}else{sb.append(array[i]);if(!isNotFirstInt)isNotFirstInt = true;}}}return sb.toString();}//BigInt数字进行加法运算public String add(BigInt bigInt) {int[] a = this.arrayint;int[] b = bigInt.arrayint;int[] result = new int[100];//根据各种情况进行结果赋值for(int i=0;i<a.length;i++){if(a[i]==0&&b[i]!=0){result[i]=b[i];}else if(a[i]!=0&&b[i]==0){result[i]=a[i];}else if(a[i]!=0&&b[i]!=0){result[i]=a[i]+b[i];}else{result[i]=0;}}//处理结果数组中超过8位的int元素的进位,该int元素截掉1位后再把其后一个元素值加一for(int i=0;i<result.length;i++){if(String.valueOf(result[i]).length()>8){result[i] = Integer.valueOf(String.valueOf(result[i]).substring(1));result[i+1] = result[i+1] + 1;}}return printArray(result);}//打印BigInt数字@Overridepublic String toString() {return printArray(arrayint);}}