PHP获取指定时间段之间的 年,月,天,时,分,秒
需求：前端传俩个标准的 时间格式过来，格式像2009-05-12 12:12:30，然后根据需要返回这个时间段的不同单位的表示
对于时间格式的校验我这里代码没贴出来，所以用的时候自己考虑加上
Class Utils { /** * format MySQL DateTime (YYYY-MM-DD hh:mm:ss) 把mysql中查找出来的数据格式转换成时间秒数 * @param string $datetime */public function fmDatetime($datetime) { $year = substr($datetime,0,4); $month = substr($datetime,5,2); $day = substr($datetime,8,2); $hour = substr($datetime,11,2); $min = substr($datetime,14,2); $sec = substr($datetime,17,2); return mktime($hour,$min,$sec,$month,$day,0+$year);}/** * * 根据俩个时间获取俩个时间的 包含的 年，月数，天数，小时，分钟，秒 * @param String $start * @param String $end * @return ArrayObject */ private function diffDateTime($DateStart,$DateEnd){$rs = array();$sYear = substr($DateStart,0,4);$eYear = substr($DateEnd,0,4);$sMonth = substr($DateStart,5,2);$eMonth = substr($DateEnd,5,2);$sDay = substr($DateStart,8,2);$eDay = substr($DateEnd,8,2);$startTime = $this->fmDatetime($DateStart);$endTime = $this->fmDatetime($DateEnd);$dis = $endTime-$startTime;//得到俩个时间的秒数$d = ceil($dis/(24*60*60));//得到天数$rs['day'] = $d;//天数$rs['hour'] = ceil($dis/(60*60));//小时$rs['minute'] = ceil($dis/60);//分钟$rs['second'] = $dis;//秒数$rs['week'] = ceil($d/7);//周$tem = ($eYear-$sYear)*12;//月份$tem1 = $eYear-$sYear;//年if($eMonth-$sMonth<0){//月份相减为负$tem +=($eMonth-$sMonth);}else if($eMonth==$sMonth){//月份相同if($eDay-$sDay>=0){$tem ++;$tem1++;}}else if($eMonth-$sMonth>0){//月份相减正负$tem1++;if($eDay-$sDay>=0){//且日期相减为正数$tem +=($eMonth-$sMonth)+1;}else{$tem +=($eMonth-$sMonth);}}$rs['month'] = $tem;$rs['year'] = $tem1;return $rs;}}