sql根据日期分组查询
我用sql2005，表（table1）如下
id zhuti riqi
1 大家好 2012-1-3
2 大 2012-1-5
3 家 2012-1-5
4 好 2012-1-10
5 欢迎 2012-1-10
6 光临 2012-1-10
我想要实现的功能是，一段sql语句实现下列输出：
2012-1-10
光临
欢迎
好
2012-1-5
家
大
2012-1-3
大家好
如何实现？请教大家了，谢谢！
[解决办法]
with t1 as (
select max(id) id,riqi from table1 group by riqi
),t2 as (
select id,zhuti from table1
),t3 as (
select id,riqi as a,1 id2 from t1
union all
select id,zhuti,2 id2 from t2
)
select a from t3 order by id desc,id2
[解决办法]
create table tb#(id int not null, zhuti varchar(10), riqi datetime)insert into tb#(id, zhuti ,riqi)select 1, '大家好','2012-1-3'union all select 2,'大',' 2012-1-5'union all select 3 , '家 ','2012-1-5'union all select 4 , '好 ','2012-1-10'union all select 5 , '欢迎','2012-1-10'union all select 6 , '光临 ','2012-1-10'select * from tb#select zhuti from(select distinct cast(year(riqi) as varchar(4))+' - '+ cast(month(riqi) as varchar(2))+' - '+ cast(day(riqi) as varchar(2)) as zhuti,riqi from tb#union allselect zhuti,riqi from tb# ) as aorder by riqi desc,zhuti--结果/*2012 - 1 - 10光临 好 欢迎2012 - 1 - 5大家 2012 - 1 - 3大家好*/
