查询同一表内多字段同时重复记录的SQL语句
比如现在有一人员表 （表名：peosons）若想将姓名、身份证号、住址这三个字段完全相同的记录查询出来 select p1.* from persons p1,persons p2 where p1.id<>p2.id and p1.cardid = p2.cardid and p1.pname = p2.pname and p1.address = p2.address 可以实现上述效果． 几个删除重复记录的SQL语句1.用rowid方法 2.用group by方法 3.用distinct方法 1。用rowid方法 据据Oracle带的rowid属性，进行判断，是否存在重复,语句如下：查数据:select * from table1 a where rowid !=(select max(rowid) from table1 b where a.name1=b.name1 and a.name2=b.name2......)删数据：delete from table1 a where rowid !=(select max(rowid) from table1 b where a.name1=b.name1 and a.name2=b.name2......) 2.group by方法 查数据:select count(num), max(name) from student --列出重复的记录数，并列出他的name属性 group by num having count(num) >1 --按num分组后找出表中num列重复，即出现次数大于一次 删数据：delete from student group by num having count(num) >1这样的话就把所有重复的都删除了。 3.用distinct方法 -对于小的表比较有用 create table table_new as select distinct * from table1 minux truncate table table1;insert into table1 select * from table_new;查询及删除重复记录的方法大全1、查找表中多余的重复记录，重复记录是根据单个字段（peopleId）来判断select * from peoplewhere peopleId in (select peopleId from people group by peopleId having count(peopleId) > 1)2、删除表中多余的重复记录，重复记录是根据单个字段（peopleId）来判断，只留有rowid最小的记录delete from people where peopleId in (select peopleId from people group by peopleId having count(peopleId) > 1)and rowid not in (select min(rowid) from people group by peopleId having count(peopleId )>1)3、查找表中多余的重复记录（多个字段） select * from vitae awhere (a.peopleId,a.seq) in (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1)4、删除表中多余的重复记录（多个字段），只留有rowid最小的记录 delete from vitae awhere (a.peopleId,a.seq) in (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1)and rowid not in (select min(rowid) from vitae group by peopleId,seq having count(*)>1)5、查找表中多余的重复记录（多个字段），不包含rowid最小的记录select * from vitae awhere (a.peopleId,a.seq) in (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1)and rowid not in (select min(rowid) from vitae group by peopleId,seq having count(*)>1)(二)比方说在A表中存在一个字段“name”，而且不同记录之间的“name”值有可能会相同，现在就是需要查询出在该表中的各记录之间，“name”值存在重复的项；Select Name,Count(*) From A Group By Name Having Count(*) > 1如果还查性别也相同大则如下:Select Name,sex,Count(*) From A Group By Name,sex Having Count(*) > 1 (三)方法一declare @max integer,@id integerdeclare cur_rows cursor local for select 主字段,count(*) from 表名 group by 主字段 having count(*) >； 1open cur_rowsfetch cur_rows into @id,@maxwhile @@fetch_status=0beginselect @max = @max -1set rowcount @maxdelete from 表名 where 主字段 = @idfetch cur_rows into @id,@maxendclose cur_rowsset rowcount 0方法二＂重复记录＂有两个意义上的重复记录，一是完全重复的记录，也即所有字段均重复的记录，二是部分关键字段重复的记录，比如Name字段重复，而其他字段不一定重复或都重复可以忽略。 1、对于第一种重复，比较容易解决，使用select distinct * from tableName就可以得到无重复记录的结果集。如果该表需要删除重复的记录（重复记录保留1条），可以按以下方法删除select distinct * into #Tmp from tableNamedrop table tableNameselect * into tableName from #Tmpdrop table #Tmp发生这种重复的原因是表设计不周产生的，增加唯一索引列即可解决。2、这类重复问题通常要求保留重复记录中的第一条记录，操作方法如下假设有重复的字段为Name,Address，要求得到这两个字段唯一的结果集select identity(int,1,1) as autoID, * into #Tmp from tableNameselect min(autoID) as autoID into #Tmp2 from #Tmp group by Name,autoIDselect * from #Tmp where autoID in(select autoID from #tmp2)最后一个select即得到了Name，Address不重复的结果集（但多了一个autoID字段，实际写时可以写在select子句中省去此列） (四)查询重复select * from tablename where id in (select id from tablename group by id having count(id) > 1)
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