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怎么解密sql2008的存儲過程

2012-09-27 
如何解密sql2008的存儲過程?我的sql2008存儲過程被別人加了with encryption語句現無法解密,請問大家有什麼

如何解密sql2008的存儲過程?
我的sql2008存儲過程被別人加了with encryption語句
現無法解密,請問大家有什麼好的方法.謝謝.


[解决办法]

SQL code
--from CSDN blog--author:unkonw--解密存储过程CREATE PROCEDURE sp_decrypt(@objectName varchar(50))ASbeginset nocount on--破解字节不受限制,适用于SQLSERVER2000存储过程,函数,视图,触发器--修正上一版视图触发器不能正确解密错误begin trandeclare @objectname1 varchar(100),@orgvarbin varbinary(8000)declare @sql1 nvarchar(4000),@sql2 varchar(8000),@sql3 nvarchar(4000),@sql4 nvarchar(4000)DECLARE @OrigSpText1 nvarchar(4000), @OrigSpText2 nvarchar(4000) , @OrigSpText3 nvarchar(4000), @resultsp nvarchar(4000)declare @i int,@status int,@type varchar(10),@parentid intdeclare @colid int,@n int,@q int,@j int,@k int,@encrypted int,@number intselect @type=xtype,@parentid=parent_obj from sysobjects where id=object_id(@ObjectName)create table #temp(number int,colid int,ctext varbinary(8000),encrypted int,status int)insert #temp SELECT number,colid,ctext,encrypted,status FROM syscomments WHERE id = object_id(@objectName)select @number=max(number) from #tempset @k=0while @k<=@number beginif exists(select 1 from syscomments where id=object_id(@objectname) and number=@k)beginif @type='P'set @sql1=(case when @number>1 then 'ALTER PROCEDURE '+ @objectName +';'+rtrim(@k)+' WITH ENCRYPTION AS 'else 'ALTER PROCEDURE '+ @objectName+' WITH ENCRYPTION AS 'end)if @type='TR'begindeclare @parent_obj varchar(255),@tr_parent_xtype varchar(10)select @parent_obj=parent_obj from sysobjects where id=object_id(@objectName)select @tr_parent_xtype=xtype from sysobjects where id=@parent_objif @tr_parent_xtype='V'beginset @sql1='ALTER TRIGGER '+@objectname+' ON '+OBJECT_NAME(@parentid)+' WITH ENCRYPTION INSTERD OF INSERT AS PRINT 1 'endelsebeginset @sql1='ALTER TRIGGER '+@objectname+' ON '+OBJECT_NAME(@parentid)+' WITH ENCRYPTION FOR INSERT AS PRINT 1 'endendif @type='FN' or @type='TF' or @type='IF'set @sql1=(case @type when 'TF' then 'ALTER FUNCTION '+ @objectName+'(@a char(1)) returns @b table(a varchar(10)) with encryption as begin insert @b select @a return end 'when 'FN' then'ALTER FUNCTION '+ @objectName+'(@a char(1)) returns char(1) with encryption as begin return @a end'when 'IF' then'ALTER FUNCTION '+ @objectName+'(@a char(1)) returns table with encryption as return select @a as a'end)if @type='V'set @sql1='ALTER VIEW '+@objectname+' WITH ENCRYPTION AS SELECT 1 as f'set @q=len(@sql1)set @sql1=@sql1+REPLICATE('-',4000-@q)select @sql2=REPLICATE('-',8000)set @sql3='exec(@sql1'select @colid=max(colid) from #temp where number=@k set @n=1while @n<=CEILING(1.0*(@colid-1)/2) and len(@sQL3)<=3996begin set @sql3=@sql3+'+@'set @n=@n+1endset @sql3=@sql3+')'exec sp_executesql @sql3,N'@Sql1 nvarchar(4000),@ varchar(8000)',@sql1=@sql1,@=@sql2endset @k=@k+1endset @k=0while @k<=@number beginif exists(select 1 from syscomments where id=object_id(@objectname) and number=@k)beginselect @colid=max(colid) from #temp where number=@k set @n=1while @n<=@colidbeginselect @OrigSpText1=ctext,@encrypted=encrypted,@status=status FROM #temp WHERE colid=@n and number=@kSET @OrigSpText3=(SELECT ctext FROM syscomments WHERE id=object_id(@objectName) and colid=@n and number=@k)if @n=1beginif @type='P'SET @OrigSpText2=(case when @number>1 then 'CREATE PROCEDURE '+ @objectName +';'+rtrim(@k)+' WITH ENCRYPTION AS 'else 'CREATE PROCEDURE '+ @objectName +' WITH ENCRYPTION AS 'end)if @type='FN' or @type='TF' or @type='IF'SET @OrigSpText2=(case @type when 'TF' then 'CREATE FUNCTION '+ @objectName+'(@a char(1)) returns @b table(a varchar(10)) with encryption as begin insert @b select @a return end 'when 'FN' then'CREATE FUNCTION '+ @objectName+'(@a char(1)) returns char(1) with encryption as begin return @a end'when 'IF' then'CREATE FUNCTION '+ @objectName+'(@a char(1)) returns table with encryption as return select @a as a'end)if @type='TR' beginif @tr_parent_xtype='V'beginset @OrigSpText2='CREATE TRIGGER '+@objectname+' ON '+OBJECT_NAME(@parentid)+' WITH ENCRYPTION INSTEAD OF INSERT AS PRINT 1 'endelsebeginset @OrigSpText2='CREATE TRIGGER '+@objectname+' ON '+OBJECT_NAME(@parentid)+' WITH ENCRYPTION FOR INSERT AS PRINT 1 'endendif @type='V'set @OrigSpText2='CREATE VIEW '+@objectname+' WITH ENCRYPTION AS SELECT 1 as f'set @q=4000-len(@OrigSpText2)set @OrigSpText2=@OrigSpText2+REPLICATE('-',@q)endelsebeginSET @OrigSpText2=REPLICATE('-', 4000)endSET @i=1SET @resultsp = replicate(N'A', (datalength(@OrigSpText1) / 2))WHILE @i<=datalength(@OrigSpText1)/2BEGINSET @resultsp = stuff(@resultsp, @i, 1, NCHAR(UNICODE(substring(@OrigSpText1, @i, 1)) ^(UNICODE(substring(@OrigSpText2, @i, 1)) ^UNICODE(substring(@OrigSpText3, @i, 1)))))SET @i=@i+1ENDset @orgvarbin=cast(@OrigSpText1 as varbinary(8000))set @resultsp=(case when @encrypted=1 then @resultsp else convert(nvarchar(4000),case when @status&2=2 then uncompress(@orgvarbin) else @orgvarbin end)end)print @resultspset @n=@n+1endendset @k=@k+1enddrop table #temprollback tranend 


[解决办法]
创建一楼的存储过程,创建成功后,再执行

SQL code
declare @object varchar(50)set @object='要解密的存储过程名称或函数名称'exec sp_decrypt  @object 

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