list的字符串转化成浮点型或整形的方法
#!/usr/bin/python
# -*- coding: UTF-8 -*-
def insertion_sort(sort_list):
iter_len = len(sort_list)
if iter_len < 2:
return sort_list
for i in range (1, iter_len):
key = sort_list[i]
j = i - 1
while j >= 0 and sort_list[j] > key:
sort_list[j+1] = sort_list[j]
j = j - 1
sort_list[j+1] = key
return sort_list
if __name__ == "__main__":
num = raw_input("enter the numbers : ").split(' ')
print num
print "the sorted nums are :"
print insertion_sort(num)
>>>
enter the numbers : 12 35 87 8 3 2
['12', '35', '87', '8', '3', '2']
the sorted nums are :
['12', '2', '3', '35', '8', '87']
上面的这个只能按ascii码排列，因为处理对象是字符串，想请教下如何才能把它当做数字来排序呢？
另外方法应该有很多种，内置函数sort，或通过类型转换后再排序等，方法不限，都可以作为答案，希望大家都贴上来，我研究研究！
谢谢！
[解决办法]
Python 2.7.3 (default, Apr 10 2012, 23:31:26) [MSC v.1500 32 bit (Intel)] on win32Type "copyright", "credits" or "license()" for more information.>>> x = ['12', '35', '87', '8', '3', '2']>>> x['12', '35', '87', '8', '3', '2']>>> x.sort(key=lambda x:int(x))>>> x['2', '3', '8', '12', '35', '87']>>>
