请问：怎样使输入的值自动去掉空格？先多谢

请教：怎样使输入的值自动去掉空格？--*--*--*--先谢谢
请输入身份证号码:<input type="text" size="20" id="asidinput" /><input type="button" value="验证" onclick="alert(cidInfo(asidinput.value))" />
　　<script>
　　var aCity={11:"北京",12:"天津",13:"河北",14:"山西",15:"内蒙古",21:"辽宁",22:"吉林",23:"黑龙江",31:"上海",32:"江苏",33:"浙江",34:"安徽",35:"福建",36:"江西",37:"山东",41:"河南",42:"湖北",43:"湖南",44:"广东",45:"广西",46:"海南",50:"重庆",51:"四川",52:"贵州",53:"云南",54:"西藏",61:"陕西",62:"甘肃",63:"青海",64:"宁夏",65:"新疆",71:"台湾",81:"香港",82:"澳门",91:"国外"} 
　　function cidInfo(sId){
　　var iSum=0
　　var info=""
　　if(!/^\d{17}(\d|x)$/i.test(sId))return 校验失败！;
　　sId=sId.replace(/x$/i,"a");
　　if(aCity[parseInt(sId.substr(0,2))]==null)return "Error:非法地区！";
　　sBirthday=sId.substr(6,4)+"-"+Number(sId.substr(10,2))+"-"+Number(sId.substr(12,2));
　　var d=new Date(sBirthday.replace(/-/g,"/"))
　　if(sBirthday!=(d.getFullYear()+"-"+ (d.getMonth()+1) + "-" + d.getDate()))return "Error:非法生日！";
　　for(var i = 17;i>=0;i --) iSum += (Math.pow(2,i) % 11) * parseInt(sId.charAt(17 - i),11)
　　if(iSum%11!=1)return "Error:非法身份证号！";
//　return aCity[parseInt(sId.substr(0,2))]+","+sBirthday+","+(sId.substr(16,1)%2?"男":"女") //
　　return aCity[parseInt(sId.substr(0,2))]+","+sBirthday+","+(sId.substr(16,1)%2?"男":"女")+"。"
　　}
　　</script>
以上如果有空格就会出错，代码改怎样修改？

[解决办法]

JScript code

function validate(event) {        if(event.keyCode == 32){            event.keyCode = 0;        }    }
[解决办法]
探讨

JScript code


function validate(event) {
        if(event.keyCode == 32){
            event.keyCode = 0;
        }
    }


加个判断吧:<input type="text" size="20" id="asidinput" onkeypress="vali……

[解决办法]
HTML code
请输入身份证号码:<input type="text" size="20" id="asidinput" onkeyup="this.value=ignoreSpaces(this.value)" /><input type="button" value="验证" onclick="alert(cidInfo(asidinput.value))" />　　<script>　　var aCity={11:"北京",12:"天津",13:"河北",14:"山西",15:"内蒙古",21:"辽宁",22:"吉林",23:"黑龙江",31:"上海",32:"江苏",33:"浙江",34:"安徽",35:"福建",36:"江西",37:"山东",41:"河南",42:"湖北",43:"湖南",44:"广东",45:"广西",46:"海南",50:"重庆",51:"四川",52:"贵州",53:"云南",54:"西藏",61:"陕西",62:"甘肃",63:"青海",64:"宁夏",65:"新疆",71:"台湾",81:"香港",82:"澳门",91:"国外"}  　　function cidInfo(sId){　　var iSum=0　　var info=""　　if(!/^\d{17}(\d|x)$/i.test(sId))return 校验失败！;　　sId=sId.replace(/x$/i,"a");　　if(aCity[parseInt(sId.substr(0,2))]==null)return "Error:非法地区！";　　sBirthday=sId.substr(6,4)+"-"+Number(sId.substr(10,2))+"-"+Number(sId.substr(12,2));　　var d=new Date(sBirthday.replace(/-/g,"/"))　　if(sBirthday!=(d.getFullYear()+"-"+ (d.getMonth()+1) + "-" + d.getDate()))return "Error:非法生日！";　　for(var i = 17;i>=0;i --) iSum += (Math.pow(2,i) % 11) * parseInt(sId.charAt(17 - i),11)　　if(iSum%11!=1)return "Error:非法身份证号！";//　return aCity[parseInt(sId.substr(0,2))]+","+sBirthday+","+(sId.substr(16,1)%2?"男":"女") //　　return aCity[parseInt(sId.substr(0,2))]+","+sBirthday+","+(sId.substr(16,1)%2?"男":"女")+"。"　　}    function ignoreSpaces(string) {    var temp = "";    string = '' + string;    splitstring = string.split(" ");    for(i = 0; i < splitstring.length; i++)    temp += splitstring[i];    return temp;    }　　</script> 
 
[解决办法]
就是你每次 键盘落下在触发个事件   这个事件通过了 再去执行你的那个方法，没通过就给个提示，或者直接帮他滤过去