关于RESERVED_BOOT_BLOCKS的有关问题，eboot大小256K ，为何只占10块

关于RESERVED_BOOT_BLOCKS的问题，eboot大小256K ，为何只占10块?
问题是这样的，eboot运行起来之后我使用 F) Low-level format the Smart Media card
这时候可以看到DNW打印如下信息
Enter your selection: f
Reserving Blocks [0x0 - 0x11] ...
...reserve complete.
Low-level format Blocks [0x12 - 0xfff] ...
...erase complete.
Reserving Blocks [0x0 - 0x11] 我不理解为什么只保留了前12块。
在代码中追踪，从功能F看起 ，

C/C++ code

  OALMSG(TRUE, (TEXT("Reserving Blocks [0x%x - 0x%x] ...\r\n"), 0, IMAGE_START_BLOCK-1));                for (i = 0; i < IMAGE_START_SECTOR; i++) {                    FMD_WriteSector(i, NULL, &si, 1);                }                OALMSG(TRUE, (TEXT("...reserve complete.\r\n")));

可以看到是IMAGE_START_BLOCK-1 ，继续往下看  
loader.h中 

C/C++ code

#define RESERVED_BOOT_BLOCKS        (NBOOT_BLOCK_SIZE + TOC_BLOCK_SIZE + EBOOT_BLOCK_SIZE)// Images start after OEM Reserved Blocks#define IMAGE_START_BLOCK           RESERVED_BOOT_BLOCKS

 RESERVED_BOOT_BLOCKS就是nboot占块+TOC块+eboot占的块  
前面两个好说 , 都是1 

C/C++ code

#define NBOOT_BLOCK                 0#define NBOOT_BLOCK_SIZE            1#define NBOOT_SECTOR                BLOCK_TO_SECTOR(NBOOT_BLOCK)// TOC @ Block 1#define TOC_BLOCK                   1#define TOC_BLOCK_SIZE              1#define TOC_SECTOR                  BLOCK_TO_SECTOR(TOC_BLOCK)// Eboot @ Block 2#define EBOOT_BLOCK                 2#define EBOOT_SECTOR_SIZE           FILE_TO_SECTOR_SIZE(EBOOT_RAM_IMAGE_SIZE)#define EBOOT_BLOCK_SIZE            SECTOR_TO_BLOCK(EBOOT_SECTOR_SIZE)#define EBOOT_SECTOR                BLOCK_TO_SECTOR(EBOOT_BLOCK)

eboot占的块是根据eboot大小得来的 EBOOT_RAM_IMAGE_SIZE
这个在上面有定义的 ，一起贴出来

C/C++ code

#define EBOOT_RAM_IMAGE_BASE        0x80038000#define EBOOT_RAM_IMAGE_SIZE        0x00040000#define EBOOT_STORE_OFFSET          0#define EBOOT_STORE_ADDRESS         (EBOOT_RAM_IMAGE_BASE + EBOOT_STORE_OFFSET)#define EBOOT_STORE_MAX_LENGTH      EBOOT_RAM_IMAGE_SIZE// BinFS work area defined in boot.bib#define BINFS_RAM_START             (0x80021000 | CACHED_TO_UNCACHED_OFFSET)   // uncached#define BINFS_RAM_LENGTH            0x5000//// Nk Memory reigions defined in config.bib...//#define ROM_RAMIMAGE_START          0x80000000#define ROM_RAMIMAGE_SIZE           0x02000000#define FILE_CACHE_START            (0x80200000 | CACHED_TO_UNCACHED_OFFSET)        // Start of file cache (temporary store                                                                                     // for flash images).// Driver globals pointer (parameter sharing memory used by bootloader and OS).//#define pBSPArgs                    ((BSP_ARGS *) IMAGE_SHARE_ARGS_UA_START)// Platform "BOOTME" root name.//#define PLATFORM_STRING         "SMDK2440"#ifndef SECTOR_SIZE#define SECTOR_SIZE                    512#endif#ifndef PAGES_PER_BLOCK#define PAGES_PER_BLOCK             32#endif#ifndef BADBLOCKMARK#define BADBLOCKMARK                0x00#endif#ifndef SECTOR_TO_BLOCK#define SECTOR_TO_BLOCK(sector)     ((sector) >> 5 )#endif#ifndef BLOCK_TO_SECTOR#define BLOCK_TO_SECTOR(block)      ((block)  << 5 )#endif

eboot大小 256K 按他的算 EBOOT_BLOCK_SIZE=256*1024/(32*512)=16 block
那就应该是一共保留18块 ，不知道我哪里算错了 ， 望指教。

[解决办法]

引用楼主 sphink 的帖子:

Reserving Blocks [0x0 - 0x11] 我不理解为什么只保留了前12块。

[解决办法]
楼主

你...........忽略了0x.....

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