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Ruby学习2 数组(2)

2012-08-27 
Ruby学习二 数组(2)ruby and watir学习之_Array 类 http://www.cnblogs.com/zhangfei/archive/2010/07/28/

Ruby学习二 数组(2)
ruby and watir学习之_Array 类

http://www.cnblogs.com/zhangfei/archive/2010/07/28/1786927.html

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Array?类说明

函数名称

说明

示例

&

数组与,返回两数组的交集

[ 1,2] & [2,3]?? ? [ 2]

*

复制数组 n 次

[ 1,2]*2??????????? ? [ 1,2,1,2]

+

返回两数组的并集,但不排除重复元素

[ 1,2]+[2,3]????? ? [ 1,2,2,3]

< < ?

追加元素,但不排除重复元素

[ 1,2]<<[2,3]???? ? [ 1,2,2,3]

|

追加元素,但排除重复元素

1,2] | [2,3]????? ? [ 1,2,3]

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-

返回第一个数组与第二个数组不同的元

?

[ 1,2]-[2,3]????? ? [ 1]

<= >

比较数组

[ 1,2]<=>[2,3]?? ? fl ase

==

比较数组,若所有元素均相等时返回真

[ 1,2]==[2,1]????? ? fl ase

assoc

从数组的每个元素中寻找指定对象

[[ 1,2],[3,4]].assoc(2)? ? [ 1,2]

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at

找到数组的第 N 个元素

负数表示逆向查找

[ " a","b","c","d","e"].at(0) ? " a" ["a","b","c","d","e"].at(-1)?? ? " e"

clear

删除数组中的所有元素

[ " a","b","c","d","e"]. clear

collect collect

用一个过程块对数组的每个元素进行处

[ " a","b","c","d"].collect {|x| x + "!" }

? [ " a!", "b!", "c!", "d!"]

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compact compact!

?

删除值为 nil 的元素后生成新数组并返 回它

[ " a",nil,"b",nil,"c",nil].compact

? [ " a", "b", "c"]

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?

d elete

?

删除元素,如果元素重复,全部删除

a = [ "a", "b", "b", "b", "c" ]

a.delete("b")

pu t s a?????? ? ["a","c"]

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?

?

d elete_at

?

删除 p o s 所指位置的元素并返回它。若

p o s 超出数组范围则返回 nil

a = %w( ant bat cat dog )

a.delete_at(2)??? ? " c at"

a????????????????????????? ? [" ant", "bat", "dog"]

a.delete_at(99)??? ? n i l

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d elete_if

根据条件删除

a = [ "a", "b", "c" ]

a.delete_if {|x| x >= "b" }?? ? [ " a"]

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each

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对数组的每个元素按值进行迭代操作

a = [ "a", "b", "c" ]

a.each {|x| print x, " -- " }

???? " a -- b -- c --"

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?

each_index

?

对数组的每个元素按索引进行迭代操作

a = [ "a", "b", "c" ]

a.each_index {|x| print x, " -- " }

? " 0 -- 1 -- 2 --"

empty?

判断数组是否为空,为空则返回真

[]. empty??? ? t rue

eql

比较两数组是否相等

[ " a","b","c"].eql?(["a","b","c"]) ? t rue

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?

fill

?

?

填充数组

[ " a","b","c","d"].fill("x")

? [ " x","x","x","x"] ["a","b","c","d"].fill("z", 2, 2)

? [ " x", "x", "z", "z"]

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fi rst

返回数组的首元素。若没有首元素则返

回 nil

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[ "q", "r", "s", "t" ].first????? ? "q "

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l ast

返回数组末尾的元素。若数组为空时,

返回 nil

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[" w " , " x " , " y " , " z"].last?????????? ? " z"

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i n clude?

?

判断数组中是否包含元素

a = [ "a", "b", "c" ]

a.include?("b")? ? t rue a.include?("z")? ? f alse

?

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i nd ex

?

返回数组中第一个==v a l 的元素的位置

a = [ "a", "b", "c" ]

a.index("b")? ? 1 a.index("z")?? ? n i l

?

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i nd exes

?

以数组形式返回其索引值与各参数值相 等的元素

a = [ "a", "b", "c", "d", "e", "f", "g" ]

a.indexes(0, 2, 4)???????? ? [ " a", "c", "e"]

a.indexes( 2, 4, 12)????? ? [ "c", "e", nil]

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?

i n sert

?

在索引为 n t h 的元素前面插入第 2 参数 以后的值

ary = %w(foo bar baz)

ary.insert 2,'a','b'

p ary???? ? [ " f oo" , "bar", "a", "b", "baz"]

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j o i n

将数组元素按一定的分隔符连接起来

[ "a", "b", "c" ].join? ? " abc"

[ "a", "b", "c" ].join("-")? ? " a-b-c"

l ength

size

返回数组长度。若数组为空则返回 0

[ 1,2,3].length??????? ? 3 [1,2,3].size??????????? ? 3

n it ems

返回非 nil 元素的个数

[ 1, nil, 3, nil, 5 ].nitems? ? 3

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p o p

?

删除末尾元素并返回它。若数组为空则 返回 nil

a = [ "a", "m", "z" ]

a.pop??????????????????????????? ? " z"

p a?????????????????????????????? ? [ " a", "m"]

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pu s h

添加新元素

[ " a","b"].push(['1','2'])

? ["a", "b", ["1", "2"]]

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rassoc

遍历数组每个元素(元素必须是数组),

匹配索引为 1 的值是否与查找的字符相 等,返回第一个相等的元素

?

a = [[15,1], [25,2], [35,2]]

p a.rassoc(2)????????????????? ? [ 25, 2]

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?

replace

?

替换数组元素

a = ["a","b"]

a.replace(["x","y","z"])

p a?????????????????????????????????? ? [ "x" , "y", "z"]

reverse reverse

将所有元素以逆序重新排列生成新数组

并返回它

?

[ " a","b","c" ].reverse? ? [ " c", "b", "a"]

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rindex

返回最后一个值相等的元素的索引值

a = [ "a","b","b","b","c"]

a.rindex("b")??????????????????????? ? 3

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?

shift

?

删除数组的首元素并返回它。剩余元素 依次提前。若数组为空返回 nil。

args = ["-m","-q","filename"]

args.shift?? ? " -m"

args?? ? [ " - q" , "filename"]

sort

sort!

从小到大排序

a = [ "d", "a", "e", "c", "b" ]

a.sort?????? ? [ " a " , "b", "c", "d", "e"]

un i q uniq

删除数组中的重复元素后生成新数组并

返回它

a = [ "a", "a", "b", "b", "c" ]

a.uniq??????????? ? [ " a " , "b", "c"]

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un s h i f t

在数组第一个元素前添加元素

a = [ "b", "c", "d" ]

a.unshift("a")????? ? [ " a " , "b", "c", "d"]

t o_ s

将数组的所有元素连接成字符串

[ " a","e","i","o"].to_s???????? ? " aeio"

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