Nginx关于Rewrite施行顺序详解.docx

2012-07-25

Nginx关于Rewrite执行顺序详解.docx,client: 127.0.0.1, server: localhost, request: GET /aaa.htmlHTTP

Nginx关于Rewrite执行顺序详解.docx

,client: 127.0.0.1, server: localhost, request: "GET /aaa.htmlHTTP/1.1", host: "localhost:9090"

, client: 127.0.0.1, server: localhost, request:"GET /aaa.html HTTP/1.1", host: "localhost:9090"

, client: 127.0.0.1, server: localhost,request: "GET /aaa.html HTTP/1.1", host: "localhost:9090"”体现了重新匹配location的流程。

,client: 127.0.0.1, server: localhost, request: "GET /aaa.htmlHTTP/1.1", host: "localhost:9090"

, client: 127.0.0.1, server: localhost, request:"GET /aaa.html HTTP/1.1", host: "localhost:9090"

, client:127.0.0.1, server: localhost, request: "GET /aaa.html HTTP/1.1",host: "localhost:9090"

??????? }??
??? ??? location? /ddd.html {
??????????? rewrite "^/ddd\.html$" /eee.html;
??????? }

简单伪代码描述下rewrite执行过程：

boolean match_finish = false;
int match_count = 0;
while(!match_finish && match_count < 10) {
??? ??? match_count ++;
??? （1）按编辑顺序执行server级的rewrite指令；
??? （2）按重写后的URI匹配location；
??? （3）
??? ??? String uri_before_location = uri;
??? ??? 按编辑顺序执行location级的rewrite指令；
??? ??? String uri_after_location = rewrite(uri);
??? ??? if(uri_before_location != uri_after_location) {
??? ??? ??? match_finish = false;??? ??? ???
??? ??? } else {
??? ??? ??? match_finish = true;
??? ??? }
??? ??? if(location rewrite has last flag) {
??? ??? ??? continue;//表示不执行后面的rewrite，直接进入下一次迭代
??? ??? }
??? ??? if(location rewrite has break flag) {
??? ??? ??? break;//表示不执行后面的rewrite，并退出循环迭代
??? ??? }
}
if(match_count <= 10) {
??? return HTTP_200;
} else {
??? return HTTP_500;
}

1 楼 tianxueer 2011-10-05 这一行有错误：while(!match_ok && match_count < 10) {

match_ok应该是match_finish吧？ 2 楼 eyesmore 2011-10-11 看得很细呵呵改了示意的 3 楼 dgww 2012-03-26 厉害，把break 和 last 说的如此透彻。只是排版嘛，哈哈，差劲 4 楼 ty173238 2012-05-08 我试了下现在重新rewrite不会执行 server级别的了只执行 location
nginx/1.0.11

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Nginx关于Rewrite施行顺序详解.docx