一道sql面试题目,有哪个高手写得出来,帮忙下
create table test2(
tid integer primary key,
ttime date,
results varchar2(50)
)
create sequence test2_seq;
insert into test2 values(test2_seq.nextval,'1-3月-2012','赢');
insert into test2 values(test2_seq.nextval,'2-3月-2012','败');
insert into test2 values(test2_seq.nextval,'1-3月-2012','赢');
insert into test2 values(test2_seq.nextval,'2-3月-2012','败');
insert into test2 values(test2_seq.nextval,'1-3月-2012','赢');
insert into test2 values(test2_seq.nextval,'1-3月-2012','败');
查询后为:
时间 赢 输
2012/3/1 3 1
2012/3/2 0 2
哪个高手帮忙写下。感激~!
[解决办法]
select to_char(ttime, 'yyyy/mm/dd') "时间", sum(decode(results, '赢', 1, 0)) "赢", sum(decode(results, '败', 1, 0)) "败" from test2 group by ttime;时间 赢 败---------- ---------- ----------2012/03/01 3 12012/03/02 0 2