字符串拆分的问题,,,,新学,,,求大侠帮助,,,急,,,
比较长的字符串="aa,1;aa,2;aa,3;bb,4;bb,5;cc,6;dd,7;dd,8;....";
如何拆分,将每一组(冒号之间的,如:aa,1)逗号前面的内容去掉,将每一组逗号后面的内容重新组合成一个字符串,如:1,2,3,4,5,6,....
新手求大侠们帮忙,,,急,,,
大热天的急的一身汗,,,,没弄出来,,,
[解决办法]
你每一组之间的不是冒号啊,命名是分号,可以这样:
string s = "aa,1;aa,2;aa,3;bb,4;bb,5;cc,6;dd,7;dd,8"; string[] parts = Regex.Split(s, @"(?:^|;)\w+,"); string result = string.Join(",", parts).Trim(','); Response.Write(result);
[解决办法]
string s ="aa,1;aa,2;aa,3;bb,4;bb,5;cc,6;dd,7;dd,8;";StringBuilder sb = new StringBuilder();string[] ss = s.Split(';');foreach(string s in ss){ sb.Append(s.Split(',')[1]+",");}Response.Write(sb.ToString.TrimEnd(','));
[解决办法]
或者这样也行:
string s = "aa,1;aa,2;aa,3;bb,4;bb,5;cc,6;dd,7;dd,8"; string result = Regex.Replace(s, @";?\w+,", ",").Trim(','); Response.Write(result);
[解决办法]
string s = "aa,1;aa,2;aa,3;bb,4;bb,5;cc,6;dd,7;dd,8"; MatchCollection mc = Regex.Matches(s, @"\w+,(\d+)"); string s1 = ""; foreach (Match m in mc) { s1 += m.Groups[1].Value + ","; } Response.Write(s1.TrimEnd(','));//1,2,3,4,5,6,7,8