sql 怎么根据指定分隔符号输出字符串

sql 如何根据指定分隔符号输出字符串？
这里分隔符号是 ‘-’，我只是想提取字符串里面的第一组数字和最后一组数字，字符串里面分割符号的数量不定，有可能3个，也有可能很多个

原始数据：
id name
1 12-32A-DDD
2 32-22F-FDD-SD
3 1-32K-F-S-DD-Q-10

希望的输出结果是：

id name name2
1 12DDD
2 32SD
3 110


[解决办法]
substring函数
[解决办法]

SQL code

select id,name=left(name,len(name)-charindex('-',name)),          name2=REVERSE(left(REVERSE(name),len(name)-charindex('-',REVERSE(name))))from tb
[解决办法]
SQL code
select id, name=left(name,len(name)-charindex('-',name)), name2=REVERSE(left(REVERSE(name),len(name)-charindex('-',REVERSE(name))))from tb
[解决办法]
SQL code
declare @t table(id int,name varchar(30));insert into @tSELECT 1, '12-32A-DDD' UNION ALLselect 2, '32-22F-FDD-SD' UNION ALLselect 3, '1-32K-F-S-DD-Q-10';WITH t1 AS(SELECT ID, Name+'-' as nameFROM @t),t2 as(SELECT ID, CONVERT(VARCHAR(30),LEFT(name,CHARINDEX('-',name)-1)) AS Subname     ,STUFF(name, 1, CHARINDEX('-',name), '') AS name, 1 AS LevelFROM t1UNION ALLSELECT t1.ID, CONVERT(VARCHAR(30),LEFT(t2.name,CHARINDEX('-',t2.name)-1))    ,STUFF(t2.name, 1, CHARINDEX('-',t2.name), ''), t2.Level+1FROM t2 JOIN     t1 ON t2.ID=t1.ID and t2.name>'')SELECT ID, MIN(CASE WHEN name>'' then subname else Null end) As name, MIN(CASE WHEN name='' then subname else Null end) As name2FROM t2where level=1 or name=''group by ID/*(3 行受影响)ID          name                           name2----------- ------------------------------ ------------------------------1           12                             DDD2           32                             SD3           1                              10警告: 聚合或其他 SET 操作消除了空值。*/