php数组编码转换出错
public function array_iconv($in_charset,$out_charset,$arr){
return eval('return '.iconv($in_charset,$out_charset,var_export($arr,true).';'));
}
我用上面的方法转化下面的数组出错
Fatal error: Call to undefined method stdClass::__set_state() in D:\soft\apache\htdocs\webtest\arrayiconv.func.php(5) : eval()'d code on line 1
array(5) {
[0]=>
object(stdClass)#8 (6) {
["optionContent"]=>
string(4) "没有"
["optionId"]=>
int(4137)
["optionImage"]=>
NULL
["optionScore"]=>
int(0)
["optionSortId"]=>
string(1) "A"
["quesId"]=>
int(1245)
}
[1]=>
object(stdClass)#9 (6) {
["optionContent"]=>
string(8) "几乎没有"
["optionId"]=>
int(4138)
["optionImage"]=>
NULL
["optionScore"]=>
int(1)
["optionSortId"]=>
string(1) "B"
["quesId"]=>
int(1245)
}
[2]=>
object(stdClass)#10 (6) {
["optionContent"]=>
string(4) "有时"
["optionId"]=>
int(4139)
["optionImage"]=>
NULL
["optionScore"]=>
int(2)
["optionSortId"]=>
string(1) "C"
["quesId"]=>
int(1245)
}
[3]=>
object(stdClass)#11 (6) {
["optionContent"]=>
string(4) "经常"
["optionId"]=>
int(4140)
["optionImage"]=>
NULL
["optionScore"]=>
int(3)
["optionSortId"]=>
string(1) "D"
["quesId"]=>
int(1245)
}
[4]=>
object(stdClass)#12 (6) {
["optionContent"]=>
string(4) "总是"
["optionId"]=>
int(4136)
["optionImage"]=>
NULL
["optionScore"]=>
int(4)
["optionSortId"]=>
string(1) "E"
["quesId"]=>
int(1245)
}
[解决办法]
老老实实递归遍历吧……
