关于RSemaphore,高手请进
一般介绍是,操作都是先wait, 再signal,但是如果先signal再wait,后果是怎样,找不到结论,一直怀疑这里有问题。自己做实验,发觉也没有问题。
我开启了两个线程,一个计时器,以下就是我的关键代码:
TInt CTestMultiThreadAppUi::ThreadProc1(void* pParam){ CTestMultiThreadAppUi* pApp = (CTestMultiThreadAppUi*)pParam; while(!pApp->iStop) { if(pApp->iLocked) { pApp->iLocked = false; pApp->m_cSemaphore.Wait(); } User::After(10000); } return 0;}TInt CTestMultiThreadAppUi::ThreadProc2(void* pParam){ CTestMultiThreadAppUi* pApp = (CTestMultiThreadAppUi*)pParam; while(!pApp->iStop) { if(pApp->iUnLocked) { pApp->iUnLocked = false; pApp->m_cSemaphore.Signal(); } User::After(10000); } return 0;}TInt CTestMultiThreadAppUi::TimerLoop(void* pParam){ CTestMultiThreadAppUi* pApp = (CTestMultiThreadAppUi*)pParam; pApp->iCount ++; if(pApp->iCount == 1000) pApp->iLocked = true; if(pApp->iCount == 100) pApp->iUnLocked = true; return 0;}